Answer:
recoil velocity of canon is 0.1039 m/s
Explanation:
given,
mass of shell = 97 kg
speed at which the shell is fired = 105 m/s
angle at which the shell is fired (θ) = 60°
mass of cannon plus car = 4.9 × 10⁴ kg
by conservation of momentum
∑ P = 0
recoil velocity of canon is 0.1039 m/s
Answer:
Gamma radiation or Cathode rays
Explanation:
by striking incident gamma or cathode rays onto the solid when placed on a photographic plate
Speed=distance/time
distance = 10,000 m
time= 27 min 30.42s but we need to convert that completely to seconds
(27x60)+30.42= 1650.12 rounded to 1650
speed=10,000/1650.12
speed=6.059063
Because when we do sig dig we round to the least number of digits we would round to 4 because 1650.12 gets rounded to 1650
so 6.059 m/s
Answer:
92.7 km
Explanation:
Since the magnetic field due to a solenoid is given by B = μ₀Ni/L where μ₀ = permeability of free space = 4π × 10⁻⁷ H/m, N = number of turns of solenoid, L = length of cardboard tube = 58 cm = 0.58 m, , i = current in wire = 2.5 A and l = length of wire.
So, N = BL/μ₀i
Since B = 2.0 kG = 2.0 × 10³ G = 2.0 × 10³ × 10⁻⁴ T = 2.0 × 10⁻¹ T = 0.2 T
So, substituting the variables into the equation, we have
N = BL/μ₀i
N = 0.2 T × 0.58 m/(4π × 10⁻⁷ H/m × 2.5 A)
N = 1.16 Tm/(31.416 × 10⁻⁷ HA/m)
N = 0.0369 × 10⁷ turns
N = 0.0369 × 10⁷ turns
N = 3.69 × 10⁵ turns
length of wire l = NC where N = number of turns and C = circumference of tube = πD where D = diameter of tube = 8.0 cm = 0.08 m
So, l = NC
= NπD
= πND
= π × 3.69 × 10⁵ turns × 0.08 m
= 0.9274 × 10⁵ m = 9.274 × 10⁴ m
= 92.74 × 10³ m
= 92.74 km
≅ 92.7 km