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Mekhanik [1.2K]
3 years ago
9

In Beijing in 2008, the Women's 3,000 meter Steeplechase became an Olympic event. What is this distance in kilometers

Mathematics
1 answer:
Naddika [18.5K]3 years ago
5 0

Answer:

The distance would be 3 kilometers

Step-by-step explanation:

Each kilometer is 1,000 meters. Divide 3,000/1,000= 3

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More help lol gvbrhf
stepan [7]

Answer:

9 at minimum

Step-by-step explanation:

a minimum of 9 because it takes a total of 8 rides to take back a full 18 cars back and the 9th ride takes back the remainder which is 0.27777777778 times 18 cars

6 0
3 years ago
I need help right now PLEASE!! !Please explain your answer
leva [86]

Answer:

Step-by-step explanation:

5 0
3 years ago
Is the triangle obtuse, acute, equilateral or right?
Stells [14]

9514 1404 393

Answer:

  obtuse

Step-by-step explanation:

The law of cosines tells you ...

  b² = a² +c² -2ac·cos(B)

Substituting for a²+c² using the given equation, we have ...

  b² = b²·cos(B)² -2ac·cos(B)

We can subtract b² to get a quadratic in standard form for cos(B).

  b²·cos(B)² -2ac·cos(B) -b² = 0

Solving this using the quadratic formula gives ...

  \cos(B)=\dfrac{-(-2ac)\pm\sqrt{(-2ac)^2-4(b^2)(-b^2)}}{2b^2}\\\\\cos(B)=\dfrac{ac}{b^2}\pm\sqrt{\left(\dfrac{ac}{b^2}\right)^2+1}

The fraction ac/b² is always positive, so the term on the right (the square root) is always greater than 1. The value of cos(B) cannot be greater than 1, so the only viable value for cos(B) is ...

  \cos(B)=\dfrac{ac}{b^2}-\sqrt{\left(\dfrac{ac}{b^2}\right)^2+1}

The value of the radical is necessarily greater than ac/b², so cos(B) is necessarily negative. When cos(B) < 0, B > 90°. The triangle is obtuse.

4 0
3 years ago
Read 2 more answers
Please help me I’m so lost !!!!
Tasya [4]

Answer:

4095

Step-by-step explanation:

\sum _{n=1}^63\left(4^{n-1}\right)\:

\sum _{n=1}^63\cdot \:4^{n-1}

Compute general progression:

\frac{3\cdot \:4^{\left(n+1\right)-1}}{3\cdot \:4^{n-1}}=4

r=4\\

a_1=3\cdot \:4^{1-1}

a_1=3

nth term is computed by:

r=4,\:a_n=3\cdot \:4^{n-1}

plug in the values n=6,\:\spacea_1=3,\:\spacer=4:

=3\cdot \frac{1-4^6}{1-4}

=4095

5 0
3 years ago
How do u solve y pluse 4 pluse 3(y pluse 2)
lesya [120]
Y + 4 + 3(y+2)    first distribute the 3
y + 4 + 3y + 6     then add like terms
4y + 10

therefore your answer should be  4y + 10
3 0
4 years ago
Read 2 more answers
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