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Jobisdone [24]
3 years ago
10

Hobb's Pet Store sells dogs and cats. Each cat costs $50 and each dog cost three times as much as a cat. At the end of one day,

Hobb's Pet Store sold a total of 25 pets and collected $2,650. How many cats were sold? *
Mathematics
2 answers:
artcher [175]3 years ago
7 0

Answer:

8 cats were sold?

Step-by-step explanation:

get 2,650÷ by 150 and you get 17.6, get 17 and subtract by 25 and you get 8.

ANTONII [103]3 years ago
4 0

Answer:

sadftgyhujk

Step-by-step explanation:

sdrtfgyhuijokl

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Step-by-step explanation: Solving  C from equation F = (9/5)C + 32 :

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2. divide by 9 you get (5/9) (F-32) = C

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4 0
3 years ago
Find the inverse of ????−7 −2
Masja [62]

Answer:

A^{-1}=\begin{bmatrix}1 & 2\\ -4 & -7\end{bmatrix}

Step-by-step explanation:

A=\begin{bmatrix}-7 & -2\\ 4 & 1\end{bmatrix}

det\ A=-7\times 1-(-2)\times 4\\\Rightarrow det\ A=1

A^{-1}=\frac{1}{det\ A}\begin{bmatrix}1 & 2\\ -4 & -7\end{bmatrix}\\\Rightarrow A^{-1}=\frac{1}{1}\begin{bmatrix}1 & 2\\ -4 & -7\end{bmatrix}\\\Rightarrow A^{-1}=\begin{bmatrix}1 & 2\\ -4 & -7\end{bmatrix}

\therefore A^{-1}=\begin{bmatrix}1 & 2\\ -4 & -7\end{bmatrix}

A.A^{-1}=\begin{bmatrix}-7 & -2\\ 4 & 1\end{bmatrix}\times \begin{bmatrix}1 & 2\\ -4 & -7\end{bmatrix}\\\Rightarrow A.A^{-1}=\begin{pmatrix}\left(-7\right)\cdot \:1+\left(-2\right)\left(-4\right)&\left(-7\right)\cdot \:2+\left(-2\right)\left(-7\right)\\ 4\cdot \:1+1\cdot \left(-4\right)&4\cdot \:2+1\cdot \left(-7\right)\end{pmatrix}\\\Rightarrow A.A^{-1}=\begin{pmatrix}1&0\\ 0&1\end{pmatrix}

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3 years ago
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7 0
3 years ago
An educational psychologist wishes to know the mean number of words a third grader can read per minute.
Rama09 [41]

Answer: 208.

Step-by-step explanation:

The formula to find the minimum sample size is given by :-

n= (\dfrac{z^*\times \sigma}{E})^2                                    (1)

, where z* = critical z-value (two tailed).                                                                      

\sigma = Standard deviation ( from prior study ) and E = Margin of error.

As per given , we have

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Confidence level = 85%

Significance level =\alpha=1-0.85=0.15

Using z-table , the critical value (two -tailed)=z^*=z_{\alpha/2}=z_{0.15/2}=z_{0.075}=1.439

As per previous study , Variance =\sigma^2=8.41

\sigma=\sqrt{8.41}=2.9

Now, the required minimum sample size = n= (\dfrac{(1.439)\times (2.9)}{0.29})^2   [Substitute the values in formula (1)]

n=(14.39)^2

n=207.0721\approx208  [ Round to the next integer]

Hence, the minimum number of third graders that must be included in a sample = 208.

5 0
3 years ago
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