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Lyrx [107]
3 years ago
14

Verify the pythagorean identity 1 + c o t ^2 θ = c s c ^2 θ

Mathematics
1 answer:
Grace [21]3 years ago
6 0

Answer: The identity is verified. See the explanation.

Step-by-step explanation:

You must keep on mind the following identities:

csc\theta=\frac{cos\theta}{sin\theta}\\\\csc\theta=\frac{1}{sin\theta}\\\\sin^2\theta+cos^2\theta=1

Therefore, by substitution, you can rewrite the identity as shown below:

1+cot^2\theta=csc^2\theta\\\\1+\frac{cos^2\theta}{sin^2\theta}=csc^2\theta

Simpliying, you obtain:

\frac{sin^2\theta+cos^2\theta}{sin^2\theta}=csc^2\theta\\\\\frac{1}{sin^2\theta}=csc^2\theta\\\\csc^2\theta=csc^2\theta

The identity is verified.

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Example: (1/3) / (4/5) = (1/3)×(5/4) . . . . . the denominator 4/5 has been inverted to 5/4 and is now a multiplier.

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8 0
3 years ago
Write an equivalent equation that does not contain parentheses for 3(k-x) = -3x-9
amm1812
3(k-x)= -3x-9
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8 0
3 years ago
1 over 7 of 2 over 5 is equal to​
natka813 [3]

Answer:

2/35

Step-by-step explanation:

1 over 7 is 1/7, of means times, and 2 over 5 is 2/5, so 1/7*2/5

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6 0
4 years ago
Which of the following shows the additive inverse property? 9 + 0 = 9 9 + 1 = 10 9 + (-1) = 8 9 + (-9) = 0
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4 years ago
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\text{Hello there!}\\\\\text{In this question, we're trying to find when both companies cost the same}\\\\\text{We know that landscaping company A charges \$50 fee plus \$18 an hour}\\\\\text{That would be represented as:}\,\,y=18x+50\\\\\text{We know that landscaping company B charges \$20 per hour and a \$30 fee}\\\\\text{That would be represented as:}\,\,y=20x+30\\\\\text{We would get both equations, put them together, and solve}\\\\18x+50=20x+30\\\\\text{Solve:}\\\\18x+50=20x+30\\

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3 0
3 years ago
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