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4 years ago

Kristin makes 12 salads in 18 minutes. How long would it take her make 20 salads?

Mathematics

1 answer:

kondor19780726 [428]4 years ago

5 0

Answer:

30 minutes for 20 salads

Step-by-step explanation:

If it takes Kristin 18 min to make 12 salads it will look like this.

18 to 12

and we need to kno how many min it will take if she makes 20 salads

x to 20

-----------

18/12=1.5min for one salad.

1.5 times 20 will give you your answer.

30 minutes.

YAY!!!

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(x + 3) is a factor of the polynomial x^3 + 2x^2 - 5x + n.<br> What is the value of n?

Igoryamba

Answer:

n = - 6

Step-by-step explanation:

Given (x + h) is a factor of a polynomial f(x) then f(- h) = 0

Here

f(x) = x³ + 2x² - 5x + n and (x + 3) is a factor then f(- 3) = 0 , that is

f(- 3) = (- 3)³ + 2(- 3)² - 5(- 3) + n = 0 , so

- 27 + 2(9) + 15 + n = 0

- 27 + 18 + 15 + n = 0

6 + n = 0 ( subtract 6 from both sides )

n = - 6

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3 years ago

Which statements are true about circle Q? Select three options. The ratio of the measure of central angle PQR to the measure of

kkurt [141]

Answer:

<h3>- The ratio of the measure of central angle PQR to the measure of the entire circle is One-eighth. </h3><h3>- The area of the shaded sector depends on the length of the radius. </h3><h3>- The area of the shaded sector depends on the area of the circle</h3>

Step-by-step explanation:

Given central angle PQR = 45°

Total angle in a circle = 360°

Ratio of the measure of central angle PQR to the measure of the entire circle is $\frac{45}{360} = \frac{1}{8}$ . This shows ratio that <u>the measure of central angle PQR to the measure of the entire circle is one-eighth</u>.

Area of a sector = $\frac{\theta}{360}*\pi r^{2}$

$\theta$ = central angle (in degree) = 45°

r = radius of the circle = 6

Area of the sector

$= \frac{45}{360}*\pi (6)^{2}\\ = \frac{1}{8}*36 \pi\\ = 4.5\pi units^{2}$

<u>The ratio of the shaded sector is 4.5πunits² not 4units²</u>

From the formula, it can be seen that the ratio of the central angle to that of the circle is multiplied by area of the circle, this shows <u>that area of the shaded sector depends on the length of the radius and the area of the circle.</u>

Since Area of the circle = πr²

Area of the circle = 36πunits²

The ratio of the area of the shaded sector to the area of the circle = $\frac{4.5\pi }{36 \pi } = \frac{1}{8}$

For length of an arc

$= \frac{45}{360}*2\pi r\\= \frac{45}{360}*2\pi (6)\\= \frac{45}{360}*12 \pi \\= \frac{12\pi }{8} \\= \frac{3\pi }{2} units$

ratio of the length of the arc to the area of the circle = $\frac{\frac{3\pi}{2} }{36\pi} = \frac{3}{72} =\frac{1}{24}$

It is therefore seen that the ratio of the area of the shaded sector to the area of the circle IS NOT equal to the ratio of the length of the arc to the area of the circle

5 0

3 years ago

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Lyrx [107]

The problem belongs to indirect variation.

formula for indirect variation is $z*x=k$