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V125BC [204]
3 years ago
5

In a collision, a 15 kg object moving with a velocity of 3 m/s transfers some of its momentum to a 5 kg object. What would be th

e velocity of the 5 kg object after the collision if the 15 kg object is still moving at 1 m/s?
Physics
1 answer:
Misha Larkins [42]3 years ago
4 0

The key to solve this problem is the conservation of momentum. The momentum of an object is defined as the product between the mass and the velocity, and it's usually labelled with the letter p:

p=mv

The total momentum is the sum of the momentums. The initial situation is the following:

m_A=15,\quad v_A=3,\quad m_B=5,\quad v_B=0

(it's not written explicitly, but I assume that the 5-kg object is still at the beginning).

So, at the beginning, the total momentum is

p=m_Av_A+m_Bv_B=15\cdot 3+5\cdot 0=45

At the end, we have

m_A=15,\quad v_A=1,\quad m_B=5,\quad v_B=x

(the mass obviously don't change, the new velocity of the 15-kg object is 1, and the velocity of the 5-kg object is unkown)

After the impact, the total momentum is

p=m_Av_A+m_Bv_B=15\cdot 1+5\cdot x=15+5x

Since the momentum is preserved, the initial and final momentum must be the same. Set an equation between the initial and final momentum and solve it for x, and you'll have the final velocity of the 5-kg object.

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A 1400 kg car is traveling east on the highway at 31 m/s and collides into the rear of a slower moving pickup truck of 2400 kg,
zloy xaker [14]

Answer: 31 m/s due east

Explanation: this question can be solved using the law of conservation of linear momentum.

This law states that in a closed or isolated system, during collision, the vector sum of momentum before collision equals the vector sum of momentum after collision.

Momentum = mass × velocity

From our question, our parameters before collision are given below as

Mass of car = mc = 1400kg

Speed of car =vc = 31 m/s (due east)

Mass of truck = mt = 2400kg

Velocity of truck = vt = 25 m/s ( due east )

After collision

Velocity of car = ?

Velocity of truck = 34 m/s ( due east )

Vector sum of momentum before collision is given as

1400 (31) + 2400 (25) = 43400 + 60000 = 103400 kgm/s

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1400 (v) + 2400(25) .... A positive value is between both momenta because they are in the same direction.

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1400v + 60000

Vector sum of momentum before collision = vector sum of momentum after collision

103400 = 1400v + 60000

103400 - 60000 = 1400v

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