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RoseWind [281]
3 years ago
8

What is word processors​

Computers and Technology
1 answer:
otez555 [7]3 years ago
8 0

A word processor is a computer program or device that provides for input, editing, formatting and output of text, often with additional features.

You might be interested in
C++ code only
nordsb [41]

Using the computational language C++ it is possible to write a code is possible to create a function that stores items like this:

<h3>Writting the code in C++: </h3>

<em>//Header files</em>

<em>#include <iostream></em>

<em>#include <string></em>

<em>#include <fstream></em>

<em>using namespace std;</em>

<em>//Class inventoryItem</em>

<em>class inventoryItem</em>

<em>{</em>

<em>public:</em>

<em>//Variable declaration</em>

<em>string itemName;</em>

<em>string itemNumber;</em>

<em>double itemPrice;</em>

<em>int itemQuantity;</em>

<em>};</em>

<em>//implementation of menuItems() function.</em>

<em>void menuItems()</em>

<em>{</em>

<em>// Display the Menu</em>

<em>cout << "=============================\n";</em>

<em>cout << " 1) Add an item to memory\n"</em>

<em><< " 2) Search memory for an item \n"</em>

<em><< " 3) List what's in memory\n"</em>

<em><< " 4) Total value on hand\n"</em>

<em><< " 5) Save to a file\n"</em>

<em><< " 6) Read from a file\n"</em>

<em><< " 0) Exit Program" << endl;</em>

<em>}</em>

<em>//main method.</em>

<em>int main()</em>

<em>{</em>

<em>//variable declaration.</em>

<em>int mnuChoice, cn = 0, d;</em>

<em>string n;</em>

<em>double sum = 0, c;</em>

<em>int temp;</em>

<em>string a, b;</em>

<em>string inputBuffer;</em>

<em>inventoryItem items[100];</em>

<em>ifstream inventoryFile("inventory.txt");</em>

<em>if (inventoryFile)</em>

<em>{</em>

<em>//store the data from the file to memory.</em>

<em>while (!(inventoryFile.eof()))</em>

<em>{</em>

<em>inventoryFile >> items[cn].itemName;</em>

<em>inventoryFile >> items[cn].itemNumber;</em>

<em>inventoryFile >> inputBuffer;</em>

<em>items[cn].itemPrice = atof(inputBuffer.c_str());</em>

<em>inventoryFile >> inputBuffer;</em>

<em>items[cn].itemQuantity = atoi(inputBuffer.c_str());</em>

<em>cn++;</em>

<em>}</em>

<em>inventoryFile.close();</em>

<em>ifstream inventoryFile("inventory.txt");</em>

<em>ofstream fout;</em>

<em>fout.open("inventory.txt");</em>

<em>do</em>

<em>{</em>

<em>menuItems();</em>

<em>cout << cn << " items stored." << endl;</em>

<em>// Prompt and read choice form the user</em>

<em>cout << "Enter your choice: ";</em>

<em>cin >> mnuChoice;</em>

<em />

<em>switch (mnuChoice)</em>

<em>{</em>

<em>//Add a new inventory item to the data in memory.</em>

<em>case 1:</em>

<em>// Prompt and read name of the item from the user</em>

<em>cout << "Enter name of the item: ";</em>

<em>cin >> inputBuffer;</em>

<em>items[cn].itemName = inputBuffer;</em>

<em>// Prompt and read itemNumber from the user</em>

<em>cout << "Enter the itemNumber: ";</em>

<em>cin >> inputBuffer;</em>

<em>items[cn].itemNumber = inputBuffer;</em>

<em>// Prompt and read itemPrice from the user</em>

<em>cout << "Enter the itemPrice: ";</em>

<em>cin >> inputBuffer;</em>

<em>items[cn].itemPrice = atof(inputBuffer.c_str());</em>

<em>// Prompt and read itemQuantity from the user</em>

<em>cout << "Enter the itemQuantity: ";</em>

<em>cin >> inputBuffer;</em>

<em>items[cn].itemQuantity = atoi(inputBuffer.c_str());</em>

<em>cn++;</em>

<em>break;</em>

<em>//Search the inventory for an item by inventory number.</em>

<em>case 2:</em>

<em>temp = 0;</em>

<em>cout << "Enter inventory itemNumber: ";</em>

<em>cin >> n;</em>

<em>for (int i = 0; i < cn&&temp != 1; i++)</em>

<em>{</em>

<em>// If found, print the stored info</em>

<em>if (items[i].itemNumber.compare(n) == 0)</em>

<em>{</em>

<em>// Display the stored information</em>

<em>cout << "Item Name" << "\t" << "Item Number" << "\t" << " Item Price" << "\t" << " Item Quantity" << endl;</em>

<em>cout << items[i].itemName << "\t " << items[i].itemNumber << " \t" << items[i].itemPrice << "\t " << items[i].itemQuantity << endl;</em>

<em>temp = 1;</em>

<em>}</em>

<em>}</em>

<em>// otherwise print 'not found'.</em>

<em>if (temp == 0)</em>

<em>{</em>

<em>cout << "Not found!!!" << endl;</em>

<em>}</em>

<em>break;</em>

<em>//List the inventory on the screen</em>

<em>case 3:</em>

<em>cout << "The data in the memory is:" << endl;</em>

<em>cout << "Item Name" << "\t" << "Item Number" << "\t" << " Item Price" << "\t" << " Item Quantity" << endl;</em>

<em>for (int i = 0; i < cn; i++)</em>

<em>{</em>

<em>cout << items[i].itemName << "\t " << items[i].itemNumber << "\t " << items[i].itemPrice << " \t" << items[i].itemQuantity << endl;</em>

<em>}</em>

<em>break;</em>

<em>// Calculate the total value on hand.</em>

<em>case 4:</em>

<em>for (int i = 0; i < cn; i++)</em>

<em>{</em>

<em>// The sum is the accumulation of all the (quantities * prices).</em>

<em>sum += items[i].itemPrice*items[i].itemQuantity;</em>

<em>}</em>

<em>cout << "sum value on hand: " << sum << endl;</em>

<em>break;</em>

<em>// Save the inventory data in the given file</em>

<em>case 5:</em>

<em>for (int i = 0; i < cn; i++)</em>

<em>{</em>

<em>if (i == cn - 1)</em>

<em>{</em>

<em />

<em>fout << items[i].itemName << " \t" << items[i].itemNumber << " \t" << items[i].itemPrice << " \t" << items[i].itemQuantity;</em>

<em>}</em>

<em>else</em>

<em>{</em>

<em />

<em>fout << items[i].itemName << " \t" << items[i].itemNumber << " \t" << items[i].itemPrice << " \t" << items[i].itemQuantity << endl;</em>

<em>}</em>

<em>}</em>

<em>break;</em>

<em>// Read the data from the file</em>

<em>case 6:</em>

<em>while (!(inventoryFile.eof()))</em>

<em>{</em>

<em>inventoryFile >> a;</em>

<em>inventoryFile >> b;</em>

<em>inventoryFile >> inputBuffer;</em>

<em>c = atof(inputBuffer.c_str());</em>

<em>inventoryFile >> inputBuffer;</em>

<em>d = atoi(inputBuffer.c_str());</em>

<em>// Dsiplays the data in the file</em>

<em />

<em>cout << a << " " << b << " " << c << " " << d << endl;</em>

<em>}</em>

<em>break;</em>

<em>}</em>

<em>// Check the menu choice is not equal to 0,</em>

<em>//if it is equal exit from the loop</em>

<em>} while (mnuChoice != 0);</em>

<em>// File closed</em>

<em>fout.close();</em>

<em>inventoryFile.close();</em>

<em>}</em>

<em>// If the inventory file does not exist</em>

<em>// and then display the error message.</em>

<em>else</em>

<em>{</em>

<em>cout << "File does not exist!" << endl;</em>

<em>}</em>

<em />

<em>return 0;</em>

<em>}</em>

See more about C++ code at brainly.com/question/17544466

#SPJ1

5 0
2 years ago
Uses computers resources from multiple locations to solve ​
kodGreya [7K]

Answer:

computers are solve all things in are life

3 0
3 years ago
Read 2 more answers
Write a brief description of what the local authorities are recommending in the news people should do to protect themselves from
lana [24]
The brief description of the local author asbestos is Hope and that's what it would too with a heart and another heart which equals 100 which equals yes
3 0
3 years ago
What is the proper structure of the variable that represents the translatable static text in Template Content?
Lubov Fominskaja [6]

{!Text.VariableName} is the proper structure of the variable that represents the translatable static text in Template Content

A. {!Text.VariableName}

<u>Explanation:</u>

In browser, content translation is possible to translate from one language to other languages, so that the end-user can easily understand the content in their own language.

Normally the text content is translated to the end-user language. As universal containers admin merger the fields so transaction output will be static text.

Suppose in browser  system prompt for translate to default language setting  once the end-user select current web page is translated to selected or default language.

8 0
3 years ago
The most accurate readings that you can take on an analog VOM are when the meter's pointer is at the A. center scale. B. extreme
frozen [14]

<u>Answer:</u>

The correct answer option is C. near right.

<u>Explanation:</u>

The most accurate readings that you can take on an analog VOM are when the meter's pointer is near right.

There are two reasons behind this: readings towards the left end are likely to be off because of the incorrect adjustment of the zero adjust screw.

While readings at the left side may result in an inaccuracy in your reading as a smaller part of the total voltage is near the full scale.

8 0
3 years ago
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