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ale4655 [162]
3 years ago
8

7x+(-7)=9x-7 what is the answer?

Mathematics
2 answers:
erastova [34]3 years ago
5 0

Answer:

x=0

Step-by-step explanation:

7x+(-7)=9x-7

Add 7 to each side

7x+(-7)7=9x-7+7

7x = 9x

Subtract 7x from each side

7x-7x = 9x-7x

0 = 2x

Divide by 2

0 = 2x/2

0 = x

grin007 [14]3 years ago
4 0

Hello,

<em>I hope you and your family are staying safe and healthy! </em>

Answer: 0

Step-by-step explanation:

7x + (-7) = 9x - 7

7x - 7 = 9x - 7

Now susbtract 9x from both sides

7x -7 - 9x = 9x - 7 - 9x\\-2x - 7 = -7

Then add 7 to both sides

-2x - 7+7=-7+7\\2x=0

x = \frac{0}{-2} \\x = 0

--------------

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Factor out the GCF from the terms of the polynomial –4y5 + 6y3 + 8y2 – 2y. A. –2y4 + 3y2 + 4y – 1 B. y(–4y4 + 6y2 + 8y – 2) C. 2
andreyandreev [35.5K]

Answer:

Option D) -2y(2y^4-3y^2-4y+1) is correct

Therefore -4y^5+6y^3+8y^2-2y=-2y(2y^4-3y^2-4y+1)

Step-by-step explanation:

Given polynomial is -4y^5+6y^3+8y^2-2y

To factorise the given polynomial by taking out the common terms of the given polynomial :

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  • =2y(-2y^4+3y^2+4y-1) ( here 2y is GCF common term so taking outside the terms of the polynomial )
  • =-2y(2y^4-3y^2-4y+1) ( now taking (-) outside )

Therefore -4y^5+6y^3+8y^2-2y=-2y(2y^4-3y^2-4y+1)

Option D) -2y(2y^4-3y^2-4y+1) is correct

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Answer:

t=\frac{44-42}{\frac{1.9}{\sqrt{40}}}=6.657    

p_v =P(t_{(39)}>6.657)=3.17x10^{-8}  

If we compare the p value and the significance level given \alpha=0.01 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, so we can conclude that the true mean is higher than 42 at 1% of signficance.  

Step-by-step explanation:

Data given and notation  

\bar X=44 represent the sample mean

s=1.9 represent the sample standard deviation

n=40 sample size  

\mu_o =42 represent the value that we want to test

\alpha=0.01 represent the significance level for the hypothesis test.  

t would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

State the null and alternative hypotheses.  

We need to conduct a hypothesis in order to check if the mean is higher than 42, the system of hypothesis would be:  

Null hypothesis:\mu \leq 42  

Alternative hypothesis:\mu > 42  

If we analyze the size for the sample is > 30 but we don't know the population deviation so is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:  

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}  (1)  

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

Calculate the statistic

We can replace in formula (1) the info given like this:  

t=\frac{44-42}{\frac{1.9}{\sqrt{40}}}=6.657    

P-value

The first step is calculate the degrees of freedom, on this case:  

df=n-1=40-1=39  

Since is a one side test the p value would be:  

p_v =P(t_{(39)}>6.657)=3.17x10^{-8}  

Conclusion  

If we compare the p value and the significance level given \alpha=0.01 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, so we can conclude that the true mean is higher than 42 at 1% of signficance.  

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Answer:

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