All categories

3 years ago

To survive the cold winter months, some plants go into a

Mathematics

1 answer:

Ierofanga [76]3 years ago

6 0

Answer:

Change in season because the colder weather causes it to dry out:/

Step-by-step explanation:

You might be interested in

Help me please please please

Grace [21]

Answer:

2x²-2x

Step-by-step explanation:

To find the area of a rectangle, you multiply the sides together.

In this case:

x × 2x-2 = x(2x-2) = 2x²-2x

7 0

3 years ago

Read 2 more answers

Describe the transformations of the following function. y=tan(2x-π)

Romashka [77]

Answer:

To quickly solve this problem, we can use a graphing tool or a calculator to plot the equation.

Please see the attached image below, to find more information about the graph

The equation is:

y = tan(2x - π)

y = tan (2*(x-π/2))

We can compare it to its parent function

g(x) = tan(x)

The answer is

Option a.

Horizontal shrink by 1/2 and horizontal shift of π/2 to the right

7 0

3 years ago

What is the value of fraction 1 over 2x3 + 5.2y when x = 2 and y = 3?

mihalych1998 [28]

I think is 1/27.6 because 2x equals 4 and times 3 equals 12. 5.2y equals 15.6. Then 15.6 plus 12 equals 27.6.

4 0

3 years ago

Find the solution set of this inequality|10x+20| ≤10

Pavlova-9 [17]

Answer:

solution is

[-3,-1]

Step-by-step explanation:

we are given

$|10x+20|\leq 10$

Firstly, we will find critical values

so, let's assume it is equal

$|10x+20|= 10$

now, we can break absolute sign

For $|10x+20|= -(10x+20)$ :

$-(10x+20)= 10$

we can solve for x

$-10x-20= 10$

Add both sides by 20

$-10x-20+20= 10+20$

$-10x= 30$

Divide both sides by -10

and we get

$x=-3$

For $|10x+20|= (10x+20)$ :

$(10x+20)= 10$

we can solve for x

$10x+20= 10$

Subtract both sides by 20

$10x+20-20= 10-20$

$10x= -10$

Divide both sides by 10

and we get

$x=-1$

so, critical values are

$x=-3$

$x=-1$

now, we can draw a number line and locate these values

and then we can check inequality on each intervals

For $(-\infty,-3)$ :

We can select any random value from this interval and plug that in inequality

and we get

we can plug x=-5

$|10\times -5+20|\leq 10$

$|-50+20|\leq 10$

$30\leq 10$

so, this is FALSE

For $[-3,-1]$ :

We can select any random value from this interval and plug that in inequality

and we get

we can plug x=-2

$|10\times -2+20|\leq 10$

$|-20+20|\leq 10$

$0\leq 10$

so, this is TRUE

For $(-1,\infty)$ :

We can select any random value from this interval and plug that in inequality

and we get

we can plug x=0

$|10\times 0+20|\leq 10$

$|0+20|\leq 10$

$20\leq 10$

so, this is FALSE

so, solution is

[-3,-1]

7 0

3 years ago

Alan sells beaded necklaces. Each large necklace sells for $5.70 and each small necklace sells for $5.10. How much will he earn

inysia [295]

Alan will make $28.50 from 5 large necklaces and $15.30 from 3 small necklaces. $43.80 in total :)

6 0

3 years ago

Read 2 more answers