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enot [183]
3 years ago
14

What force was applied to an object if 35 J of work was done and the object moved 7 m? Show your work.

Physics
1 answer:
ahrayia [7]3 years ago
8 0

Answer:

5 N

Explanation:

The work done by a force on an object is (assuming that the direction of the force is parallel to the displacement of the object):

W=Fd

where

F is the magnitude of the force

d is the displacement of the object

In this problem, we know that:

W = 35 J is the work done

d = 7 m is the displacement of the object

Therefore, we can re-arrange the equation to calculate the force applied:

F=\frac{W}{d}=\frac{35 J}{7 m}=5 N

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Two positive charges of magnitude 20 micro C and 100 micro C are placed at a distance of 150cm. Calculate the force of repulsion
Luba_88 [7]

first \: positive \: charge = q1 = 20

1micro \: =   {1}^{ - 6}

1q = 20 \times 10 {}^{ - 6}

second \: charge = q2 = 100 \times 10 {}^{ - 6}

formula = f =  \frac{k \times q1 × q2}{d {}^{2} }

remember

k = 9 \times  {10}^{9}

change distance 150cm to 1.5m

putting values

f =\frac{9 \times 10 {}^{9} \times 20  \times 10 {}^{ - 6} \times 100 \times  {10}^{ - 6}   }{1.5 {}^{2} }

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3 years ago
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kogti [31]

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C. nuclear to electrical

6 0
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You are using a bucket of water in a science experiment. You conclude that water is a liquid because
Harrizon [31]
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8 0
4 years ago
a quickly moving house cat has 10 j of kinetic energy at speed v. at what speed will the cat have 20 j of kinetic energy
Brums [2.3K]

Answer:

2.00v

Explanation:

3 0
3 years ago
6. You are in an airplane going down a runway currently going 24 m/s and accelerating at 8 m/s?
Allisa [31]

Answer:

The time taken by the airplane to take off, t = 11.46 s

Explanation:

Given data,

The initial velocity of the airplane, u = 24 m/s

The acceleration of the plane, a = 8 m/s

The distance covered until take off, d = 800 m

Using the III equation of motion,

                      v² = u² +2as

                           = 24² + 2 x 8 x 800

                           = 13376

                       v = 115.65 m/s

Using the first equation of motion,

                      v = u + at

                       t = (v-u) / a

                         = (115.65 - 24) / 8

                         = 11.46 s

Hence, the time taken by the airplane to take off, t = 11.46 s

4 0
3 years ago
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