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enot [183]
3 years ago
14

What force was applied to an object if 35 J of work was done and the object moved 7 m? Show your work.

Physics
1 answer:
ahrayia [7]3 years ago
8 0

Answer:

5 N

Explanation:

The work done by a force on an object is (assuming that the direction of the force is parallel to the displacement of the object):

W=Fd

where

F is the magnitude of the force

d is the displacement of the object

In this problem, we know that:

W = 35 J is the work done

d = 7 m is the displacement of the object

Therefore, we can re-arrange the equation to calculate the force applied:

F=\frac{W}{d}=\frac{35 J}{7 m}=5 N

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Anton [14]
The child's linear speed is
              
    <em> (pi / 5) x (the child's distance from the center of the ride, in feet)</em>

                                                                                        feet per second.
5 0
3 years ago
A wave emitted from a source has a frequency of 10 Hz and wavelength 2.5 m. How much time will it take to reach a person located
const2013 [10]

Answer:

time taken by the wave to reach the person is 0.2 s

Explanation:

As we know that the speed of the wave is given as

v = \lambda f

here we know that the wavelength of the wave is

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f = 10 Hz

now speed of the wave is given as

v = 10(2.5)

v = 25 m/s

Now time taken by the wave to reach 5 m distance is

t = \frac{L}{v}

t = \frac{5}{25}

t = 0.2 s

4 0
3 years ago
if you put a pencil in a cup of water, it looks as if it is broken and larger in the water. This is because light waves
vladimir1956 [14]

Answer:

When light enters from air to water i.e. it is moving from rarer to denser medium, it changes its original path as there is a change of speed of light and deflects itself towards the normal. This is known as the refraction of light and this is why a pencil in a cup of water looks as if it is broken and larger.

Explanation:

5 0
3 years ago
A parallel-plate capacitor with circular plates of radius R is being charged by a battery, which provides a constant current. At
NikAS [45]

To solve this problem it is necessary to apply the concepts related to the magnetic field.

According to the information, the magnetic field INSIDE the plates is,

B=\frac{1}{2} \mu \epsilon_0 r

Where,

\mu =Permeability constant

\epsilon_0 =Electromotive force

r = Radius

From this deduction we can verify that the distance is proportional to the field

B \propto r

Then the distance relationship would be given by

\frac{r}{R} = \frac{B}{B_{max}}

r =\frac{B}{B_{max}} R

r = \frac{0.5B_{max}}{B_{max}}R

r = 0.5R

On the outside, however, it is defined by

B = \frac{\mu_0 i_d}{2\pi r}

Here the magnetic field is inversely proportional to the distance, that is

B \not\propto r

Then,

\frac{r}{R} = \frac{B_{max}{B}}

r = \frac{B_{max}{B}}R

r = \frac{B_{max}{0.5B_{max}}}R

r = 2R

7 0
3 years ago
How many watts are used when 6000 joules of energy are consumed in 5 hours?
Ray Of Light [21]
Power = energy / time
Time should be in seconds
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Hope it helped!
7 0
3 years ago
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