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enot [183]
3 years ago
14

What force was applied to an object if 35 J of work was done and the object moved 7 m? Show your work.

Physics
1 answer:
ahrayia [7]3 years ago
8 0

Answer:

5 N

Explanation:

The work done by a force on an object is (assuming that the direction of the force is parallel to the displacement of the object):

W=Fd

where

F is the magnitude of the force

d is the displacement of the object

In this problem, we know that:

W = 35 J is the work done

d = 7 m is the displacement of the object

Therefore, we can re-arrange the equation to calculate the force applied:

F=\frac{W}{d}=\frac{35 J}{7 m}=5 N

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Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions here.

<span>KE = 1/2mv^2 = (1/2)(2000)(2^2) = 4000 J This must equal the net work acting on the car. W=Fd The net force is 1140-950= 190N. so, d=W/F = 4000/190 = 21.05 m</span>
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a current of 5 ampere is passed for 2 hours in an electric iron having a resistance of 100 ohms calculate the heat produced
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Answer:

\boxed{\sf Heat \ produced \ (H) = 5 \ kWh}

Given:

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Explanation:

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\boxed{ \bold{ \sf H = I^2Rt}}

Substituting values of I, R & t in the equation:

\sf \implies H =  {5}^{2}  \times 100 \times 2 \\  \\ \sf \implies H = 25 \times 100 \times 2 \\  \\  \sf \implies H = 5000  \\  \\ \sf \implies H = 5 \: kWh

\therefore

Heat developed (H) in the electric iron = 15 kWh

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