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SCORPION-xisa [38]
3 years ago
8

The electric field in a certain region of Earth's atmosphere is directed vertically down. At an altitude of 439 m the field has

magnitude 50.7 N/C; at an altitude of 361 m, the magnitude is 84.3 N/C. Find the net amount of charge contained in a cube 78 m on edge, with horizontal faces at altitudes of 361 m and 439 m.
Physics
1 answer:
aksik [14]3 years ago
6 0

Answer: 1.8* 10^-6 C

Explanation: Considering the flux for the electric in the two surface corresponding to the cube.

For the top surface, the flux is = 50.7 N/C* 78*78 m^2= 50.7*6084=

-3.084*10^5 C*m^2 ( the electric field and the normal to the surface have opossite directions)

For the bottom surface, the flux is 84.3 N/C * 78*78 m^2= 84.3*6084=

5.128 *10^5 C m^2

By the Gauss Law, the net flux of the electric field is the total charge closed by the gaussian surface.

So the net flux is 2.044 * 10^5 C*m^2

The net flux= Q/ε0 then

the total charge is  2.044 * 10^5 C*m^2 * 8.85 * 10^-12= 1.8* 10^-6 C

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This question would be a piece o' cake, except that we don't know your observations, your data, or your conclusions.

We also don't know the first method, the second method, the accuracy of either method, the displacement method, or what you found out from this investigation.

Otherwise, like I said, this is really no problem.

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3 years ago
Modern commercial airliners are largely made of aluminum, a light and strong metal. But the fact that aluminum is cheap enough t
iVinArrow [24]

Answer:

 n = 291 people

Explanation:

To solve this interesting problem we are going to take some data from the tables, the density of 7075 aluminum is 2.8 103 kg / m³, the density of 316 stainless steel is 7980 kg / m³, where we have selected one of the most used alloys in for its resistance.

The average mass of a passenger is mo = 80kg and the Boeing 747 aircraft can carry 550 passengers and a crew of 18 people with a length of 70.66 m,

Let's start by calculating the mass of the empty plane and the mass of the passengers

         ρ_Al = m_Al / V

         m_Al = ρ_Al V

         m_passenger= #_pasajeros 80

         m_passenger = 550 m₀

         

The total mass of the plane is

          M = m_passengers + m_Al

If the plane is built face to face, the mass of this material is

        ρ_Acero = m_steel / V

         

the total mass of avino is

         M = m_pasajeros` + m_steel

As they indicate the total mass of the plane must remain constant

         m_passengers + m_Al = m_passengers` + m_steel

let's substitute the values

         550 m₀ + 2.8 103 V = n m₀ + 7.98 103 V

where V is the volume of the material used which is the same in both cases

         n = 550 mo + (2.8 - 7.98) 103 V = n mo

         n = n = 550 + (2.8 - 7.98) 103 V / mo

The calculation of the volume of material used depends on the thickness of the sheet and the resistance of the material, if it assumes that it has the same thickness, e = 1 cm, approximate the volume to the length of the circle by the length of the cylinder by the thickness

         V = (2π r) L e

  the diameter of the plane approximately the height of the person

         d = 1.8 m

         V = 2π (1.8 / 2) 70.66 1 10⁻²

         V = 3.9957 m³

  we substitute

          n = 550 - 5.18 10³ (3.9957) / 80

          n = 550 - 258.7

          n = 291 people

3 0
3 years ago
A soccer ball of mass 0.4 kg is moving horizontally with a speed of 20 m/s when it is kicked by a player. The kicking force is s
amid [387]

Answer:

v_{f} = 74 m/s, F = 230 N

Explanation:

We can work on this exercise using the relationship between momentum and moment

        I = ∫ F dt = Δp

bold indicates vectors

we can write this equations in its components

X axis

       Fₓ t = m ( -v_{xo})

Y axis  

        t = m (v_{yf} - v_{yo})

in this case with the ball it travels horizontally v_{yo} = 0

Let's use trigonometry to write the final velocities and the force

        sin 30 = v_{yf} / vf

        cos 30 = v_{xf} / vf

        v_{yf} = vf sin 30

        v_{xf} = vf cos 30

         sin40 = F_{y} / F

         F_{y} = F sin 40

         cos 40 = Fₓ / F

         Fₓ = F cos 40

let's substitute

      F cos 40 t = m ( cos 30 - vₓ₀)

      F sin 40 t = m (v_{f} sin 30-0)

we have two equations and two unknowns, so the system can be solved

        F cos 40 0.1 = 0.4 (v_{f} cos 30 - 20)

        F sin 40 0.1 = 0.4 v_{f} sin 30

we clear fen the second equation and subtitles in the first

         F = 4 sin30 /sin40     v_{f}

         F = 3.111 v_{f}

        (3,111 v_{f}) cos 40 = 4 v_{f} cos 30 - 80

        v_{f} (3,111 cos 40 -4 cos30) = - 80

        v_{f} (- 1.0812) = - 80

        v_{f} = 73.99

        v_{f} = 74 m/s

now we can calculate the force

          F = 3.111 73.99

          F = 230 N

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igomit [66]

Answer:

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Explanation:

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Katena32 [7]

<em>L</em><em>ike the alto in a choir the octavina plays the lower melody . what musical element does this tell?</em>

answer : melody....

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3 years ago
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