Answer:
-2 m/s
Explanation:
The computation of the acceleration of the block is as follows:
The volume of the block is
V = 1kg ÷ 1,000 kg/m^3 = 1 ÷ 1,000 m^3
Now at the time of submerging in the oil
Net force is
= -2 m/s
The answer is d. Each of its particles becomes surrounded by water molecules.
Notice that when you dissolve a solid compound in the water, it is no longer visible in or eyes, it mixes in the water, it is because it is being divided into smaller particles and each particles were surrounded by the water molecules.
When an electron in a hydrogen atom transitions from the state of n=6 to n=1, a photon with an energy of 13.2 eV is released.
<h3>What components make up a photon?</h3>
- A photon is a microscopic particle that is part of electromagnetic radiation waves.
- Maxwell demonstrated that photons are merely electric fields flowing through space.
- A single photon can trigger a response from sensors in the retina.
<h3>What is the difference between an electron and a photon?</h3>
- Photons and electrons. One of the fundamental quantum-mechanical particles is an electron, although photons also exist and have entirely distinct properties.
- While the electron is a subatomic particle found in every atom, the photon is a sort of elementary particle that serves as an energy carrier.
learn more about photon here
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Indirect but I not sure so please wait for someone else too answer also cause I don’t want you too get it wrong because if me if I the wrong answer
Answer:
The collision is not elastic. The system increases his kinetic energy m*v₀² times.
Explanation:
Assuming no external forces acting during the collision, total momentum must be conserved.
Considering the information provided, we can write the momentum conservation equation as follows:
m*v₀ = -m*v₀ + 2*m*vf
Solving for vf, we arrive to this somehow surprising result:
vf = v₀ (in the same direction that m was moving before the collision).
In order to determine if the collision was elastic, or not, we need to calculate the kinetic energy of the system before and after the collision:
K₀ = 1/2*m*v₀²
Kf = 1/2*m*v₀² (due to the object of mass m, as the kinetic energy is always positive) + 1/2 (2m) * v₀²
⇒Kf = 1/2*m*v₀² + 1/2 (2m) * v₀² = 3/2*m*v₀²
ΔK = Kf - K₀ = 3/2*m*v₀² - 1/2*m*v₀² = m*v₀²
As there is a net difference between the final and initial kinetic energies, and the total kinetic energy must be conserved in an elastic collision (by definition) we conclude that the collision is not elastic, and the change in the kinetic energy of the system is equal to m*v₀².
