Where does the energy released in a nuclear decay reaction come from

The largest and brightest galaxies are those that contain _____.

user100 [1]

They contain quasars

6 0

3 years ago

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Which missing item would complete this beta decay reaction?

Flauer [41]

For us to understand the missing item that would complete beta decay reaction, we need to achieve in depth understanding of chemical formulas and nuclear symbols. Next is to have great comprehension of the following points:
<span>1.) Neutron in nucleus breaks down and changes into a proton.
2) Then it emits an electron, as well as an anti-neutrino which go into space.
3) Lastly, atomic number continuously goes UP while mass number remains unchanged.</span>

8 0

3 years ago

Which was a common goal of Spanish and British explorers in the Southeastern region of North America?

slamgirl [31]

Answer:

B

Explanation:

To discover gold

6 0

3 years ago

What cells in the nervous signals travel through the nervous system

kirill115 [55]

Answer:Although the nervous system is very complex, nervous tissue consists of just two basic types of nerve cells: neurons and glial cells Neurons are the structural and functional units of the nervous system They transmit electrical signals, called nerve impulses. Glial cells provide support for neurons.

Explanation:

3 0

3 years ago

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What should be the spring constant k of a spring designed to bring a 1200 kg car to rest from a speed of 85 km/h so that the occ

borishaifa [10]

Answer:

k = 5178.8 N/m

Explanation:

As we know that spring mass system will oscillate at angular frequency given as

$\omega = \sqrt{\frac{k}{m}}$

now we have

$\omega = \sqrt{\frac{k}{1200}}$

now the maximum acceleration of the spring block system is at its maximum compression state which is given as

$a = \omega^2 A$

here A= maximum compression of the spring

so here in order to find maximum compression of the spring we will use energy conservation as we know that initial total kinetic energy of the car will convert into spring potential energy

$\frac{1}{2}mv^2 = \frac{1}{2}kA^2$