Answer:
22.95g
Explanation:
Given parameters:
Percentage by mass of silver in silver iodide = 45.9%
Mass of silver iodide given = 50g
Unknown:
Mass of silver in silver iodide = ?
Solution:
The formula of the compound is;
Silver iodide = AgI
Since the percentage by mass of silver in the compound is 45.9%;
Mass of silver = percentage by mass of silver x mass of AgI
Mass of silver = 
x 50 = 22.95g
I'm not sure. It is rare for BH3 to be in this form.
The value of current solubility product is calculated as below
K = (Ag+)( Cl-)
Ag+ = 0.01 M
Cl-= 1 x10^-5M
K is therefore = 1 x10^-5 x 0.01 = 1 x10 ^ -7 M
The K obtained is greater than Ksp
that is K> KSp
1x10^-7 > 1.7 x10 ^-10
will precipitation of AgCl form?
yes the precipitation of AgCl will be formed since K> KSP
Mud is a mixture. It's mixed with water, soil, silt and clay.
Answer is: concentration is 1.3 ppm.
Parts-per-million (10⁻⁶) is present at one-millionth of a gram per gram of sample solution, for example mg/kg.
d(Cu) = 0.0013 g/L; mass concentration of copper.
d(H₂O) = 1.00 g/mL; density of water.
m(H₂O) = V(H₂O) · d(H₂O).
m(H₂O) = 1000 mL · 1 g/mL.
m(H₂O) = 1000 g ÷ 1000 g/kg.
m(H₂O) = 1 kg; mass of water.
m(Cu) = 0.0013 g · 1000 mg/g.
m(Cu) = 1.3 mg; mass of coppper.
concentration = 1.3 mg ÷ 1 kg.
concentration = 1.3 mg/kg.
concentration = 1.3 ppm.
