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3 years ago

Which of the following would correctly be termed "miscible"? sugar in water alcohol in water oil in water salt in oil

2 answers:

4 0

Alcohol in water is correctly termed "miscible". The equivalent answer is B.
If this has helped you, consider my answer to become the Brainliest!

elena-s [515]3 years ago

3 0

The correct answer would be Alcohol in water.
I know this right because i just finished my assignment and got it right.

I also can tell you water and oil does not dissolve in each other so that answer could be crossed out. Sugar in water is also wrong on the fact their not both liquids which in that case salt in oil would wrong. Hoped this helped you!

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In some places timber companies remove all the trees from entire hillside when they are harvesting logs and farmers till the soi

laila [671]

Answer:

The timber companies removing all the trees from entire hillside when they are harvesting logs is a practice that could cause the following when it is time to plant in spring:

1. It could affect the quality of plant needed nutrients in the soil and beneficial microorganism population in the soil which could impact negatively the planting season.

2. Trees serves as protection of soil nutrients against wind erosions, so the soil nutrients would be affected.

The farmers tilling the soil means preparing the soil for a farming season as the following effect:

1. Helps control weed for the planting season.

2. This practice could further encourage soil erosion if not done well.

3. Tilling the soil could make leftover plants from the felling of trees mix well with the soil and also add nutrients to the soil when they decay.

8 0

3 years ago

Consider a solution that contains 0.274 M potassium chloride and 0.155 M magnesium chloride.

solong [7]

Answer:

Concentration of chloride ions = 0.584M

Explanation:

The step by step calculations is shown as attached below.

3 0

3 years ago

For the following reaction, KcKc = 255 at 1000 KK.

bonufazy [111]

Answer :

The equilibrium concentration of CO is, 0.016 M

The equilibrium concentration of Cl₂ is, 0.034 M

The equilibrium concentration of COCl₂ is, 0.139 M

Explanation :

The given chemical reaction is:

$CO(g)+Cl_2(g)\rightleftharpoons COCl_2(g)$

Initial conc. 0.1550 0.173 0

At eqm. (0.1550-x) (0.173-x) x

As we are given:

$K_c=255$

The expression for equilibrium constant is:

$K_c=\frac{[COCl_2]}{[CO][Cl_2]}$

Now put all the given values in this expression, we get:

$255=\frac{(x)}{(0.1550-x)\times (0.173-x)}$

x = 0.139 and x = 0.193

We are neglecting value of x = 0.193 because equilibrium concentration can not be more than initial concentration.

Thus, we are taking value of x = 0.139

The equilibrium concentration of CO = (0.1550-x) = (0.1550-0.139) = 0.016 M

The equilibrium concentration of Cl₂ = (0.173-x) = (0.173-0.139) = 0.034 M

The equilibrium concentration of COCl₂ = x = 0.139 M

5 0

3 years ago

13. Which could be true about an unknown sample with a pH of 7? (2 points)

laiz [17]

The best and most correct answer among the choices provided by your question is the first choice or letter A.

A ph of 7 contains only water.

I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!

5 0

3 years ago

Read 2 more answers

What is △n for the following equation in relating Kc to Kp?

Nimfa-mama [501]

Answer:

-1

Explanation:

The relation between Kp and Kc is given below:

$K_p= K_c\times (RT)^{\Delta n}$

Where,

Kp is the pressure equilibrium constant

Kc is the molar equilibrium constant

R is gas constant , 0.082057 L atm.mol⁻¹K⁻¹

T is the temperature in Kelvins

Δn = (No. of moles of gaseous products)-(No. of moles of gaseous reactants)

For the first equilibrium reaction:

$2Na_{(s)}+2H_2O_{(l)}\rightleftharpoons 2NaOH_{(aq)}+2H_2_{(g)}$

<u>Δn = (No. of moles of gaseous products)-(No. of moles of gaseous reactants) = (2+1)-(2+2) = -1 </u>

<u></u>

7 0

3 years ago