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Bess [88]
3 years ago
12

Which of the following would correctly be termed "miscible"? sugar in water alcohol in water oil in water salt in oil

Chemistry
2 answers:
beks73 [17]3 years ago
4 0
Alcohol in water is correctly termed "miscible". The equivalent answer is B.
If this has helped you, consider my answer to become the Brainliest!
elena-s [515]3 years ago
3 0
The correct answer would be Alcohol in water.
I know this right because i just finished my assignment and got it right.

I also can tell you water and oil does not dissolve in each other so that answer could be crossed out. Sugar in water is also wrong on the fact their not both liquids which in that case salt in oil would wrong. Hoped this helped you!
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Give two examples of activities performed by the veterinarian
AURORKA [14]

Answer:

exp:

two ways of activities performed by a veterinarian is:

performing surgery and checkups.

8 0
3 years ago
What is the mole ratio of N2 to H2 to NH3?
Alexeev081 [22]

Answer:

the answer is 1:3:2

Hope this helps, let me know if you need any other help, Stoichiometry is hard

4 0
4 years ago
A standard solution is prepared for the analysis of fluoxymesterone (c20h29fo3; 336 g/mol), an anabolic steroid. a stock solutio
-Dominant- [34]

<em>Answer:</em>

  • The concentration of new solution will be 1×10∧-7 M.

<em>Solution:</em>

<em>Data Given </em>

       given mass of fluoxymesterone =16.8mg = 0.0168 g

       molar mass  of fluoxymesterone = 336g/mol

       vol. of fluoxymesterone = 500.0 ml = 0.500 L

      Stock Molarity of  fluoxymesterone = (0.0168/336)÷0.500 = 1×10∧-4 M

So applying dilution formula

                   Stock Solution :  New Solution

                                 M1.V1 = M2.V2

       ( 1×10∧-4 M) × (1×10∧-6 L) = M2 × 0.001 L

     [( 1×10∧-4) × (1×10∧-6)]÷[0.001] = M2

     1 × 10∧-7 = M2

<em>Result:</em>

  • The concentration of new solution M2 will be  1 × 10∧-7
3 0
3 years ago
What is the oxidation number of C in NaHCO3?
Phoenix [80]
Na = +1
H = +1
O = -2
Total charge is 0:
1 + 1 + C + 3 x -2 = 0
C = 4
4 0
3 years ago
What is the total mass of D-glucose dissolved in a 2-μL aliquot of the solution used for this experiment?
RideAnS [48]

Answer:

The total mass of D-Glucose dissolved in a 2μL aliquot is 1 E-4 g

Explanation:

providing a solution to 5% weight-volume as found in commerce:

⇒ % 5 = (5g d-glucose/ 100 mL sln)×100

⇒ 0.05 =  g C6H12O6/mL sln

⇒ g C6H12O6 = (2 μL sln)×(0.001 mL/μL)×(0.05 g C6H12O6/mL sln)

⇒ g C6H12O6 = 1 E-4 g C6H12O6

5 0
4 years ago
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