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alisha [4.7K]
3 years ago
14

Is anyone good at chemistry if so can someone please help me NO LINKS PLEASE

Chemistry
1 answer:
joja [24]3 years ago
3 0

Answer:

1. Mass of New atom = 208

2. Atomic number of the new atom is 82

3. Symbol of the new atom is Pb

Explanation:

²¹²₈₄Po —> ⁴₂He + ᴬZX

1. Determination of the mass A of the new atom.

212 = 4 + A

Collect like terms

212 – 4 = A

208 = A

A = 208

Therefore, the mass of the new atom is 208

2. Determination of the atomic number of the new atom.

84 = 2 + Z

Collect like terms

84 – 2 = Z

82 = Z

Z = 82

Therefore, the atomic number of the new atom is 82

3. Determination of symbol of the new atom

The atomic number of the new atom is 82. Comparing the atomic number of the new atom (i.e 82) with those in the periodic table, the new atom is Lead.

Lead has a symbol of Pb

Thus,

Mass of new atom (A) = 208

Atomic number of new atom (Z) = 82

Symbol of new atom (X) = Pb

Therefore,

ᴬZX = ²⁰⁸₈₂Pb

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Why is an atom regarded as electrically unstable​
meriva

Answer: An atom can be considered unstable in one of two ways. If it picks up or loses an electron, it becomes electrically charged and highly reactive. Such electrically charged atoms are known as ions. Instability can also occur in the nucleus when the number of protons and neutrons is unbalanced.

Explanation:

5 0
3 years ago
If 27.3% of a sample of silver-112 decays in 1.52 hours, what is the half-life (in hours to 3 decimal places)?
ICE Princess25 [194]

<u>Answer:</u> The half life of the sample of silver-112 is 3.303 hours.

<u>Explanation:</u>

All radioactive decay processes undergoes first order reaction.

To calculate the rate constant for first order reaction, we use the integrated rate law equation for first order, which is:

k=\frac{2.303}{t}\log \frac{[A_o]}{[A]}

where,

k = rate constant = ?

t = time taken = 1.52 hrs

[A_o] = Initial concentration of reactant = 100 g

[A] = Concentration of reactant left after time 't' = [100 - 27.3] = 72.7 g

Putting values in above equation, we get:

k=\frac{2.303}{1.52hrs}\log \frac{100}{72.7}\\\\k= 0.2098hr^{-1}

To calculate the half life period of first order reaction, we use the equation:

t_{1/2}=\frac{0.693}{k}

where,

t_{1/2} = half life period of first order reaction = ?

k = rate constant = 0.2098hr^{-1}

Putting values in above equation, we get:

t_{1/2}=\frac{0.693}{0.2098hr^{-1}}\\\\t_{1/2}=3.303hrs

Hence, the half life of the sample of silver-112 is 3.303 hours.

6 0
3 years ago
Which expression is equal to the number of grams (g) in 2.43 kilograms (kg)?
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An excess of mg(s) is added to 100.ml of 0.400 m hcl. at 0c and 1 atm pressure, what volume of h 2 (g) can be obtained?
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T - temperature in Kelvin - 0 °C + 273 = 273 K
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