Explanation:
The oxidation number of chlorine can be -1, 0, +1, +3, +4, +5, or +7, depending on the substance containing the chlorine. The most common oxidation numbers are -1 (as in HCl and NaCl ) and 0 (as in Cl2 ).
Answer:
D
An electric circuit is best described as a loop.
the flow of electrons
Explanation:
Answer:
Empirical formula is PNCl₂
Explanation:
Percent composition means that 100 g of compound has x g of each element.
In 100 g of compound x, we have 26.73 g of P, 12.09 g of N, 61.18 g of Cl.
So, let's make some rules of three:
In 100 g of compound we have 26.73 g of P, 12.09 g of N, 61.18 g of Cl
In 579.43 g of compound we have:
(579.43 . 26.73) / 100 = 155 g of P
(579.43 . 12.09) / 100 = 70 g of N
(579.43 . 61.18) / 100 = 354 g of Cl
Let's convert the mass of the elements in moles.
155 g of P / 30.97 g/mol = 5 P
70 g / 14 g/mol = 5 N
354 g / 35.45 g/mol = 10 Cl
20 protons
20 electrons ( as much elctrons as protons because there has to be same positive and negative to have a neutral atom)
And the number of neutrons depends of the mass number but in that case, I think that it's a Calcium atom (Ca) and so there are 20 netrons.
Answer:
On the particulate level: 1 molecule of H₂(g) reacts with 1 molecule of Cl₂(g) to form 2 molecules of HCl(g).
On the molar level: 1 mole of H₂(g) reacts with 1 mole of Cl₂(g) to form 2 moles of HCl(g).
Explanation:
Let's consider the following equation.
H₂(g) + Cl₂(g) → 2 HCl(g)
We can use the balanced equation to interpret the changes in two levels: the particulate level and the molar level.
On the particulate level, we consider discrete molecules.
On the particulate level: 1 molecule of H₂(g) reacts with 1 molecule of Cl₂(g) to form 2 molecules of HCl(g).
On the molar level, we think in terms of moles, considering 1 mole of particles = 6.02 × 10²³ particles.
On the molar level: 1 mole of H₂(g) reacts with 1 mole of Cl₂(g) to form 2 moles of HCl(g).
