All categories

3 years ago

When vibrational motion in an object increases, which is a true statement?

1 answer:

6 0

When vibrational motion in an object increases, the statement that is true is that the kinetic energy temperature and thermal energy increases. The correct option among all the options that are given in the question is the second option or option "B". I hope the answer comes to your help.

You might be interested in

The power rating of a light bulb (such as a 100-W bulb) is the power it dissipates when connected across a 120-V potential diffe

bazaltina [42]

To solve this problem we will apply the concepts related to the calculation of power, from the two electrical forms:

$P = VI$

$P = \frac{V^2}{R}$

Here,

V = Voltage

I = Current

R= Resistance

P = Power

PART A)

$R = \frac{V^2}{P}$

Replacing,

$R = \frac{(120V)^2}{150W}$

$R = 96\Omega$

Resistance of bulb is $96\Omega$

PART B)

$I = \frac{P}{V}$

$I = \frac{150W}{120V}$

$I = 1.25A$

The bulb will draw 1.25A current

7 0

3 years ago

A sample contains 20 kg of radioactive material. The decay constant of the material is 0.179 per second. If the amount of time t

Nataly [62]

Answer:

Explanation:

Given

N0 = 20kg (original substance)

decay constant λ = 0.179/sec

time t = 300s

We are to find N(t)

Using the formula;

n(t) = N0e^-λt

Substitute the given values

N(t) = 20e^-(0.179)(300)

N(t) = 20e^(-53.7)

N(t) = 20(4.7885)

N(t) =143.055

To know how much of the original material that is active, we will find N(t)/N0 = 143.055/20 = 7.152

About 7 times the original material is still radioactive

4 0

3 years ago

What is light intensity?

Stels [109]

Answer:

Light intensity refers to the strength or amount of light produced by a specific light source .

8 0

3 years ago

A force of 10N is applied by a boy while lifting a 20,000g mass. How much does it accelerate by?

Tanya [424]

Answer:

0.5 $m/s^{2}$

Explanation:

20000g to kg = $\frac{20000}{1000}$ = 20 kg

f = ma

a = $\frac{f}{m}$

a = $\frac{10}{20}$

a = $\frac{1}{2}$

a = 0.5 $m/s^{2}$

8 0

3 years ago

A window has a glass surface of 2907 cm2 and a thickness of 5.6 mm. Find the rate of energy transfer by conduction through this

butalik [34]

Answer:

2.30714 W

-16.38071 W

Explanation:

k = Heat conduction coefficient = 0.8 W/(m·°C)

A = Area = 2907 cm²

l = Thickness = 5.6 mm

$T_2$ = Outside temperature

$T_1$ = Inside temperature

Rate of heat transfer is given by

$Q=\frac{kA(T_2-T_1)}{l}\\\Rightarrow Q=\frac{0.8\times 2907\times 10^{-6}\times (81-71)\times \frac{5}{9}}{5.6\times 10^{-3}}\\\Rightarrow Q=2.30714\ W$

The rate of energy transfer is 2.30714 W

$Q=\frac{kA(T_2-T_1)}{l}\\\Rightarrow Q=\frac{0.8\times 2907\times 10^{-6}\times (0-71)\times \frac{5}{9}}{5.6\times 10^{-3}}\\\Rightarrow Q=-16.38071\ W$

The rate of energy transfer is -16.38071 W

7 0

3 years ago