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goldfiish [28.3K]
3 years ago
15

Which variable would be most useful in determining the number of people eligible for retirement benefits in a certain year?

Physics
1 answer:
KonstantinChe [14]3 years ago
8 0

The answer is

D. Age structure

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Choose the correct statement regarding projectile motion in the absence of air resistance. Assume the object is at sea level mov
pishuonlain [190]

Answer:

Explanation:

The magnitude of the acceleration in the x direction is always zero: TRUE.

At the apex, in the y direction the velocity is zero and the accelration is positive. TRUE.

At the apex, in the x direction, the velocity is zero and the acceleration is zero. FALSE. The accelration is zero, but the velocity is the same it had when it was shot.

The magnitude of the velocity in the y direction is always constant. FALSE, it's subject to gravity and it's velocity varies as v=v_0 - 9.81ms^{-2} t

At the apex, in the Y direction, the velocity is negative and the acceleration is zero. FALSE. Velocity is zero, Acceleration is 9.81 ms^{-2}, towards the negative y axis

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3 years ago
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aleksandr82 [10.1K]
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4 years ago
Which choice best describes how scientists learn new information during investigations?
OlgaM077 [116]

Answer:

C

Explanation:

During investigations a scientist needs to observe, investigate, collect data and put together the information they collect.

4 0
3 years ago
A 100-kg block being released from rest from a height of 1.0 m. It then takes it 1.40 s to reach the floor. What is the mass m o
dimulka [17.4K]

Complete Question

The complete question is shown on the first uploaded image

Answer:

The mass of the other block is  m_1 = 81.14 \ kg

Explanation:

From the question we are told that

   Mass of the first block is  m_1 = 100 \  kg

   The height is  s =  1.0 \  m

   The time it takes it is  t = 1.40 \  s

 Generally from kinematic equation

       s =  ut + \frac{1}{2} at^2

Here u  is the initial velocity which zero given that it was at rest initially

So

     s =  0 * t + \frac{1}{2} at^2

=>  s =   \frac{1}{2} at^2

=> 1 =   \frac{1}{2}*  a *  (1.40 )^2

=>  a = 1.0204 \  m/s^2

Generally from the diagram the resultant force due to the weight of the first object and the tension on the string is  mathematically represented as

      mg - T = ma

=>   T  =  m g - ma

=>   T  =  m(g - a)

=>   T  =  877.96 \  N

Generally from the diagram the resultant force due to the weight of the second object and the tension on the string is  mathematically represented as  

     T - m_1g  =  m_1 a

=>   877.96  =  m_1 (a + g)

=>   877.96  =  m_1 (1.0204  + 9.8 )

=>   m_1 = 81.14 \ kg

5 0
3 years ago
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