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hodyreva [135]
2 years ago
10

Accelerates uniformly at 2.0 ms2 for 10.0s. Calculate its final velocity​

Physics
1 answer:
Crazy boy [7]2 years ago
4 0

Answer:

The distance is

=

7

m

Explanation:

Apply the equation of motion

s

(

t

)

=

u

t

+

1

2

a

t

2

The initial velocity is

u

=

0

m

s

−

1

The acceleration is

a

=

2

m

s

−

2

Therefore, when

t

=

3

s

, we get

s

(

3

)

=

0

+

1

2

⋅

2

⋅

3

2

=

9

m

and when

t

=

4

s

s

(

4

)

=

0

+

1

2

⋅

2

⋅

4

2

=

16

m

Therefore,

The distance travelled in the fourth second is

d

=

s

(

4

)

−

s

(

3

)

=

16

−

9

=

7

m

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Explanation:

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Standing at a crosswalk, you hear a frequency of 530 Hz from the siren of an approaching ambulance. After the ambulance passes,
malfutka [58]

Answer:

_s = 37.77 m / s

Explanation:

This is an exercise of the Doppler effect that the change in the frequency of the sound due to the relative speed of the source and the observer, in this case the observer is still and the source is the one that moves closer to the observer, for which relation that describes the process is

                    f ’= f₀  \frac{v}{v - v_s}

where d ’= 530 Make

when the ambulance passes away from the observer the relationship is

                    f ’’ = f₀ \frac{v}{v + v_s}

where d ’’ = 424 beam

let's write the two expressions

               f ’ (v-v_s) = fo v

               f ’’  (v + v_s) = fo v

let's solve the system, subtract the two equations

                v (f ’- f’ ’) - v_s (f’ + f ’’) = 0

                v_s = v \frac{ f' - f''}{ f' + f''}

the speed of sound is v = 340 m / s

let's calculate

                 v_s = 340 (\frac{ 530 -424}{530+424} )

                 v_s = 340 (\frac{106}{954})

                  v_s = 37.77 m / s

5 0
2 years ago
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