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Bogdan [553]
3 years ago
10

??? I know it's hard to make out but please help xx15 points

Chemistry
1 answer:
baherus [9]3 years ago
7 0
Answer is C. 2, 3 and 5 shows how as the number of carbon increase,  butane, pentane and hexane (4,5 and 6 carbons) the octane number does decrease
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Zinc chloride (ZnCl2) and hydrogen (H2) are the products of a single replacement reaction. What are the reactants of this reacti
timurjin [86]

Answer:

B Zn+2HCI

Explanation:

4 0
3 years ago
Describe what an alchemist does
Zielflug [23.3K]
Yes what he saiddddd
6 0
2 years ago
C2H5OH(l) + 3O2(g) → 2CO2(g) + 3H2O(l), ΔH = –1.37 × 103 kJ For the combustion of ethyl alcohol as described in the above equati
babymother [125]

Answer:

The true statements are: I. The reaction is exothermic.

II. The enthalpy change would be different if gaseous water was produced.

Explanation:

The given chemical reaction: C₂H₅OH(l) + 3O₂(g) → 2CO₂(g) + 3H₂O(l),  ΔH= -1.37×10³kJ

1. In an exothermic reaction, heat or energy is released from the system to the surrounding. Thus for an exothermic process the change in enthalpy is less than 0 or negative (ΔH < 0) .

Since the enthalpy change for a combustion reaction is negative. <u>Therefore, the given reaction is exothermic.</u>

2. The change in enthalpy (ΔH) of a reaction is equal to difference of the sum of standard enthalpy of formation (ΔHf°) of the products and the reactants.

ΔHr° = ∑ n.ΔHf°(products) − ∑ n.ΔHf°(reactants)

As the value of ΔHf° of water in gaseous state and liquid state is not the same.

<u>Therefore, the enthalpy change of the reaction will be different, if gaseous water was present instead of liquid water.</u>

3. An oxidation-reduction reaction or a redox reaction involves simultaneous reduction and oxidation processes.

The given chemical reaction, represents the combustion reaction of ethanol.

Since combustion reactions are redox reactions. <u>Therefore, the given combustion reaction is an oxidation-reduction reaction.</u>

4. According to the ideal gas equation: P.V =n.R.T

Volume (V) ∝ n (number of moles of gas)

Since the number of moles (n) of gaseous reactants is 3 and number of moles of gaseous (n) products is 2.

<u>Therefore, the volume occupied by 3 moles of the reactant gaseous molecules will be more than 2 moles product gaseous molecules.</u>

3 0
3 years ago
Convert 23.92inHg to torr.
White raven [17]
<h3><u>Answer;</u> </h3>

= 607.568 Torr

<h3><u>Explanation; </u></h3>

1 in of mercury is equivalent to 25.4 Torr  

Therefore;

23.92 InHg will be equal to;

23.92 × 25.4  

<u>= 607.568 Torr</u>

7 0
3 years ago
IMFs are NOT found in what type of<br> substances?
ExtremeBDS [4]

Answer:

False

Explanation:

8 0
3 years ago
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