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BaLLatris [955]
2 years ago
12

The total oxide ion charge in a formula unit of Mn2O3 is 6-. What is the charge on each manganese ion ?

Chemistry
1 answer:
Rom4ik [11]2 years ago
5 0

Answer:

Mn= +3 charge

Explanation:

if you take what we know, and that would be the charge of oxygen, we know that oxygen has a 2- charge and there are 3 sets of O^2-  so multiply the number of oxygen times the charge and you get 6-.

Next set up an equation as listed in the picture  which will be 2(x)=6

and that is the charge of the Mn ion.

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Is a pH of 7 high pH or neutral??
navik [9.2K]

Answer:

neutral

Explanation:

pH range goes from 0-14, since 7 is in between 0 and 14, it is neutral.

7 0
3 years ago
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Which formula contains two nonmetals
VLD [36.1K]

Answer:

Nonmetal + Nonmetal —> covalent compound (usually)

Explanation:

Covalent compounds are formed when two nonmetals react with each other.

7 0
3 years ago
3. Crystalline structural unit of barium metal is a body-centered cubic cell. The edge length of the unit cell is 5.02x10-8 cm.
tiny-mole [99]

Answer:

The Avogadro's  number is N_A     =  6.02289 *10^{23}

Explanation:

From the question we are told that

   The edge length is  L   = 5.02 * 10^{-8} \ cm= \frac{5.02 * 10^{-8} }{100}  =  5.02 * 10^{-10}

    The density of the metal is \rho =  5.30\ g/cm^3 = 5.30 * \frac{g}{cm^3}  * \frac{1*10^6}{1*10^3} = 5.30 *10^3kg/m^3

     The molar mass of  Ba is  Z  =  137.3 \ g/mol = \frac{137.3}{1000} =  0.1373 \  kg / mol

     

Generally the volume of a unit cell is  

       V =  L^3

substituting value

        V =  [5.02 *10^{-10}]^3

         V = 1.265*10^{-28}\ m^3  

From the question we are told that 68% of the unit cell is occupied by Ba atoms and that the structure is a metal which implies that the crystalline structure will be  (BCC),

The volume of barium atom is  

        V_a  =  \frac{V}{2}  * 0.68

substituting value

        V_a  =  \frac{ 1.265*10^{-28}}{2}  * 0.68

        V_a  = 4.301 *10^{-29} \ m^3

The Molar mass of barium is mathematically represented as

      Z  =  N_A V_a *  \rho

Where N_A is the Avogadro's number

 So  

      N_A     =   \frac{ Z}{ V_a *  \rho}

substituting value

     N_A     =   \frac{ 0.1373}{ 4.301*10^{-29} *  5.3*10^{3}}

     N_A     =  6.02289 *10^{23}

4 0
2 years ago
PLEASE HELP QUICK AS POSSIBLE!!!!
GalinKa [24]

Answer:

4180J

Explanation:

(25.0g)(4.184J/g°C)(75°C-35.0°C)

(25.0g)(40.0°C)(4.184J/g°C)

(1.00*10³g°C)(4.184J/g°C) = 4184J

use sig figs:

4180J

8 0
3 years ago
The burning of a sample of propane
r-ruslan [8.4K]

Answer:

70.0°C

Explanation:

We are given;

  • Amount of heat generated by propane as 104.6 kJ or 104600 Joules
  • Mass of water is 500 g
  • Initial temperature as 20.0 ° C

We are required to determine the final temperature of water;

Taking the initial temperature is x°C

We know that the specific heat of water is 4.18 J/g°C

Quantity of heat = Mass × specific heat × change in temperature

In this case;

Change in temp =(x-20)° C

Therefore;

104600 J = 500 g × 4.18 J/g°C × (x-20)

104600 J = 2090x -41800

146400 = 2090 x

  x = 70.0479

     =70.0 °C

Thus, the final temperature of water is 70.0°C

7 0
3 years ago
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