<u>Answer:</u> The given amount of iron reacts with 9.0 moles of 
and produce 6.0 moles of 
<u>Explanation:</u>
We are given:
Moles of iron = 12.0 moles
The chemical equation for the rusting of iron follows:
By Stoichiometry of the reaction:
4 moles of iron reacts with 3 moles of oxygen gas
So, 12.0 moles of iron will react with = 
of oxygen gas
- <u>For iron (III) oxide:</u>
By Stoichiometry of the reaction:
4 moles of iron produces 2 moles of iron (III) oxide
So, 12.0 moles of iron will produce = 
of iron (III) oxide
Hence, the given amount of iron reacts with 9.0 moles of and produce 6.0 moles of
Answer:
All decrease
Explanation:
Trust, and I just got this question and got it right
Answer:
5.46% is the percent by mass concentration of the solution.
Explanation:
Mass of LiBr= 8.2 g(Solute)
Mass of solution = 150 g (Solution)
Mass of solution = Mass of solute + Mass of solvent
Mass of solute < Mass of solvent (Always)
Mass of water = 150 g - 8.2 g = 141.8 g (solvent)
Mass percentage is given as:
5.46% is the percent by mass concentration of the solution.
Answer : Yes , H2SO4 is an arrhenius acid
<h2>Explanations : </h2>
• An ,Arrhenius acid ,is a substance that ,dissociates, in water to form ,hydrogen ions (H+).
,
• In other words, an arrhenius acid increases the H+ ion concentration in aqueous solution.
,
• This can be represented by the equation :
• Therefore, H2SO4 is a strong arrhenius acid.
