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Zina [86]
2 years ago
11

In a spacecraft tge carbon dioxide exhaled by the astronaut can be removed by the reaction with lithium hydroxide, LiOH accordin

g to the following; CO2(g) + LiOH(g) = LiOH(s) + H2O(l) how many moles of Lithium hydroxide are required to react with 30 moles of CO2, average exhaled by each person

Chemistry
1 answer:
quester [9]2 years ago
3 0

Answer:

30 moles

Explanation:

From the equation it is a one - to - one reaction

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explain the relationship between the rate of effusion of a gas and its molar mass. methane gas (ch4) effuses 3.4 times faster th
Musya8 [376]

The molar mass of the unknown gas is 184.96 g/mol

<h3>Graham's law of diffusion </h3>

This states that the rate of diffusion of a gas is inversely proportional to the square root of the molar mass i.e

R ∝ 1/ √M

R₁/R₂ = √(M₂/M₁)

<h3>How to determine the molar mass of the unknown gas </h3>

The following data were obtained from the question:

  • Rate of unknown gas (R₁) = R
  • Rate of CH₄ (R₂) = 3.4R
  • Molar mass of CH₄ (M₂) = 16 g/mol
  • Molar mass of unknown gas (M₁) =?

The molar mass of the unknown gas can be obtained as follow:

R₁/R₂ = √(M₂/M₁)

R / 3.4R = √(16 / M₁)

1 / 3.4 = √(16 / M₁)

Square both side

(1 / 3.4)² = 16 / M₁

Cross multiply

(1 / 3.4)² × M₁ = 16

Divide both side by (1 / 3.4)²

M₁ = 16 / (1 / 3.4)²

M₁ = 184.96 g/mol

Learn more about Graham's law of diffusion:

brainly.com/question/14004529

#SPJ1

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2 years ago
8. __H2 + __O2-&gt; __H2O
Rus_ich [418]

Anser:

Explanation:

hope this helps

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2 years ago
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