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SCORPION-xisa [38]
3 years ago
9

4. A steel cable spanning a river is 220.000 m long when the temperature is 30.°C.

Physics
1 answer:
romanna [79]3 years ago
5 0

Answer:

219.9208  m

Explanation:

The new length is given by

New length= Original length *(1-Temperature change*coefficient of

thermal expansion of steel)

Here, the change in temperature is 30^{\circ}-0^{\circ}= 30^{\circ}

New length= 220.000(1-30*12x10^{-6}=219.9208m

Therefore, the new length will be 219.9208 m

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160×10⁶ bar

Explanation:

Bulk modulus is defined as:

K = -V ΔP / ΔV

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ΔP is the change in pressure,

and ΔV is the change in volume.

Given:

K = 160×10⁹ Pa

ΔV = -0.01V

160×10⁹ Pa = -V ΔP / (-0.01V)

160×10⁹ Pa = ΔP / 0.01

ΔP = 160×10¹¹ Pa

ΔP = 160×10⁶ bar

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Read 2 more answers
You will begin with a relatively standard calculation.Consider a concave spherical mirror with a radius of curvature equal to 60
Strike441 [17]

a) 30.0 cm

For any mirror, the radius of curvature is twice the focal length:

r = 2f

where

r is the radius of curvature

f is the focal length

For the mirror in this problem, we have

r = 60.0 cm is the radius of curvature

Therefore, solving the equation above for f, we find its focal length:

f=\frac{r}{2}=\frac{60.0 cm}{2}=30.0 cm

b) 90 cm

The mirror equation is:

\frac{1}{s'}=\frac{1}{f}-\frac{1}{s}

where

s' is the distance of the image from the mirror

f is the focal length

s is the distance of the object from the mirror

For the situation in the problem, we have

f = +30.0 cm is the focal length (positive for a concave mirror)

s = 45.0 cm is the object distance from the mirror

Solving the formula for s', we find

\frac{1}{s'}=\frac{1}{30.0 cm}-\frac{1}{45.0 cm}=0.011 cm^{-1}

s'=\frac{1}{0.011 cm^{-1}}=90 cm

c) -2

The magnification of the mirror is given by

M=-\frac{s'}{s}

where in this problem we have

s' = 90 cm is the image distance

s = 45.0 cm is the object distance

Solving the equation, we find:

M=-\frac{90 cm}{45 cm}=-2

So, the magnification is -2.

d) -12.0 cm

The magnification can also be rewritten as

M=\frac{y'}{y}

where

y' is the height of the image

y is the heigth of the object

In this problem, we know

y = 6.0 cm is the height of the object

M = -2 is the magnification

Solving the equation for y', we find

y'=My=(-2)(6.0 cm)=-12.0 cm

and the negative sign means that the image is inverted.

Part e and f are exactly identical as part b) and c).

6 0
4 years ago
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