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ale4655 [162]
2 years ago
12

Osteoporosis is a condition that makes bones more

Physics
1 answer:
erastova [34]2 years ago
7 0

the answer for this question is c

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A stretched rubber band is an example of which type potential energy
Alenkinab [10]

Answer: elastic potential energy

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What refers to a soils ability to transmit water
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Permeability is also called as hydraulic conductivity, which refers to the ability of a soil to conduct water. ... Composition is of four basic categories: water, air, organic matter and minerals.

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idk, i knew a bit and looked it up to make sure i was correct.

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3 years ago
What will occur if a resistor with high resistance is inserted into a circuit?
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If the resistor is in series with the rest of the circuit then a is the correct answer. The voltage across the resistor in series with another resistor is
V \frac{R}{R+r}
where R is the big resistor and r is the small one and V is the total voltage drop across both.  This is called a voltage divider
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Which example possesses mechanical potential energy?. A. a taut guitar string. B. an oscillating pendulum. C. a roller coaster r
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The taut guitar string haspotencial energy which we can see in action.</span>  <span>· so option a is correct.</span>
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One end of a thin rod is attached to a pivot, about which it can rotate without friction. Air resistance is absent. The rod has
Mars2501 [29]

Answer:

6.86 m/s

Explanation:

This problem can be solved by doing the total energy balance, i.e:

initial (KE + PE)  = final (KE + PE). { KE = Kinetic Energy and PE = Potential Energy}

Since the rod comes to a halt at the topmost position, the KE final is 0. Therefore, all the KE initial is changed to PE, i.e, ΔKE = ΔPE.

Now, at the initial position (the rod hanging vertically down), the bottom-most end is given a velocity of v0. The initial angular velocity(ω) of the rod is given by ω = v/r , where v is the velocity of a particle on the rod and r is the distance of this particle from the axis.

Now, taking v = v0 and r = length of the rod(L), we get ω = v0/ 0.8 rad/s

The rotational KE of the rod is given by KE = 0.5Iω², where I is the moment of inertia of the rod about the axis of rotation and this is given by I = 1/3mL², where L is the length of the rod. Therefore, KE = 1/2ω²1/3mL² = 1/6ω²mL². Also, ω = v0/L, hence KE = 1/6m(v0)²

This KE is equal to the change in PE of the rod. Since the rod is uniform, the center of mass of the rod is at its center and is therefore at a distane of L/2 from the axis of rotation in the downward direction and at the final position, it is at a distance of L/2 in the upward direction. Hence ΔPE = mgL/2 + mgL/2 = mgL. (g = 9.8 m/s²)

Now, 1/6m(v0)² = mgL ⇒ v0 = \sqrt{6gL}

Hence, v0 = 6.86 m/s

4 0
3 years ago
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