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ira [324]
3 years ago
5

Modern psychologists have proposed the facial feedback hypothesis based on the theories of

Physics
2 answers:
aev [14]3 years ago
8 0

Answer:

Charles Darwin

Explanation:

The facial feedback hypothesis states that facial movement can influence emotional experience.

He suggested that physiological changes caused by an emotion had a direct impact on that emotions, rather than being just the consequence of that emotion. He wrote:

"The free expression by outward signs of an emotion intensifies it. On the other hand, the repression, as far as this is possible, of all outward signs softens our emotions... Even the simulation of an emotion tends to arouse it in our minds."

sveta [45]3 years ago
6 0
Charles Darwin was the first to state that physiological changes have an impact on the emotion emotion rather than just being a result of it. Therefore, modern facial feedback hypothesis is based on the theories of Charles Darwin.
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What is the force of gravity for a 12 kg turkey?<br><br> Please help asap
pogonyaev

Answer: 117.6N

Explanation:

By the second Newton's law, we know that:

F = m*a

F = force

m = mass

a = acceleration

We know that in the surface of the Earth, the gravitational acceleration is g = 9.8m/s^2.

Then we just can input that acceleration in the above equation, and also replace m by 12kg, and find that the force due the gravity is:

F = 12kg*9.8m/s^2 = 117.6N

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3 years ago
1) How many AU make up a light-year?
MrRissso [65]

Answer:..

1.One light-year = 63,240 AU

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Are you for or against using nuclear energy?
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Against but it really depends on the situation

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How does the speed of an object relate to the energy of the object
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3 years ago
Planets are not uniform inside. Normally, they are densest at the center and have decreasing density outward toward the surface.
SSSSS [86.1K]

Answer:

a = 9.94 m/s²

Explanation:

given,

density at center= 1.6 x 10⁴ kg/m³

density at the surface = 2100 Kg/m³

volume mass density as function of distance

\rho(r) = ar^2 - br^3

r is the radius of the spherical shell

dr is the thickness

volume of shell

dV = 4 \pi r^2 dr

mass of shell

dM = \rho(r)dV

\rho = \rho_0 - br

now,

dM = (\rho_0 - br)(4 \pi r^2)dr

integrating both side

M = \int_0^{R} (\rho_0 - br)(4 \pi r^2)dr

M = \dfrac{4\pi}{3}R^3\rho_0 - \pi R^4(\dfrac{\rho_0-\rho}{R})

M = \pi R^3(\dfrac{\rho_0}{3}+\rho)

we know,

a = \dfrac{GM}{R^2}

a = \dfrac{G( \pi R^3(\dfrac{\rho_0}{3}+\rho))}{R^2}

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a = 9.94 m/s²

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3 years ago
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