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telo118 [61]
3 years ago
8

For a wave, what term is defined as the maximum height of a crest, or depth of a trough, relative to the normal level

Physics
1 answer:
BabaBlast [244]3 years ago
4 0

Answer:

Amplitude.

Explanation:

Radio waves can be defined as an electromagnetic wave that has its frequency ranging from 30 GHz to 300 GHz and its wavelength between 1mm and 3000m. Therefore, radio waves are a series of repetitive valleys and peaks that are typically characterized of having the longest wavelength in the electromagnetic spectrum.

Basically, as a result of radio waves having long wavelengths, they are mainly used in long-distance communications such as the carriage and transmission of data. Some examples of communication technologies that uses radio waves are radio set, mobile phones, television etc.

For a wave, an amplitude is defined as the maximum height of a crest, or depth of a trough, relative to the normal level

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Red light of wavelength 633 nmnm from a helium-neon laser passes through a slit 0.360 mmmm wide. The diffraction pattern is obse
777dan777 [17]

Answer:

      Δy= 5,075 10⁻⁶ m

Explanation:

The expression that describes the interference phenomenon is

      d sin θ = (m + ½) λ

As the observation is on a distant screen

     tan θ = y / x

     tan θ= sin θ/cos θ

As in ethanes I will experience the separation of the vines is small and the distance to the big screen

          tan θ = sin θ

Let's replace

     d y / x = (m + ½) λ

The width of a bright stripe at the difference in distance  

     y₁ = (m + ½) λ x / d

     m = 1

      y₁ = 3/2 λ x / d

Let's use m = 1, we look for the following interference,

             m = 2

             y₂ = (2+ ½) λ x / d

The distance to the screen is constant x₁ = x₂ = x₀

The width of the bright stripe is

           Δy = λ x / d (5/2 -3/2)

           Δy = 630 10⁻⁹ 2.90 /0.360 10⁻³ (1)

           Δy= 5,075 10⁻⁶ m

8 0
3 years ago
If you carry out an experiment measuring the weight and mass of objects in one particular location on the earth, what relation w
Elina [12.6K]
The answer is letter C.

Weight (on Earth) is the force due to the mass of Earth attracting whatever mass is subject of discussion.

The force of attraction between any two masses is called Newton's Law of Universal Gravitation:

G \frac{m_1m_2}{d^2}

G is simply a given constant.

If we're at the surface of Eath, m_1 refers to the mass of the Earth, m_2 to the mass of whatever is on the surface of Earth, and d to the radius of Earth. 

Normally, we define a constant g to be equal to G \frac{M}{r^2}; in which M is the mass of Earth and r the radius of earth; g happens to be around 9.8.

By that, we adapt the Law of Universal Gravitation to objects on the surface of Earth, we call that force Weight.

W=mg

As you can see, weight is directly proportional to mass, more mass implies more weight.
8 0
4 years ago
What are the two conditions for equilibrium of a rigid body? how would this experiment demonstrate their validity?.
Naddik [55]

Answer:

They're are Conditions .... (L00K D0WN.)

Explanation:

Conditions for equilibrium require that the sum of all external forces acting on the body is zero (first condition of equilibrium), and the sum of all external torques from external forces is zero (second condition of equilibrium). These two conditions must be simultaneously satisfied in equilibrium.

4 0
2 years ago
Calculate the angular velocity and linea­r velocity of both wheels assuming the l­arger wheel rotates at 120 revolutions p­er mi
IRINA_888 [86]
<span>120 revolutions p­er min is (20RPM)
120revolutions is 240 Pi radians (because 1 revolution is 2Pi rad)

angular velocity
w= 240Pixf, f is the frequency and f= 1/T, T =1mn=60s=period, so f=1/60=0.01Hz
so w = 240*Pi*0.01=12.56 rad /s
linear velocity can be found with
V =Rx w,    
V=12.56 R the value depends on what value is the radius of both wheels

</span>
6 0
3 years ago
A girl on a motorbike passes by at a speed of 15 m/sec. her mass is 55 kg what is her kinetic energy
MrRissso [65]
K = m*v^{2}  / 2&#10;&#10;K = 50 * 225 / 2&#10;&#10;K = 5625 J
5 0
4 years ago
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