<span>Write the equation of the line that satisfies the given conditions, Express the final equation in standard form. Contains the point (2,5) and is parallel to the line x-2y=-5
The given equation can be written 2y=x+5; y = (1/2)x+(5/2)
It's slope is 1/2
So any line parallel to it has slope = 1/2
If the line also passes thru (2,5), 5 = (1/2)2+b; b=4
Therefore the equation you want is y = (1/2)x+4</span>
Answer:
Step-by-step explanation:
zeroes are when you plug in that x value and get y=0
therefore if you set x = that number and solve for 0 you get a "function"
multiplying these together will yield the complete 3rd degree polynomial
x = 1
x-1=0
x=7
x-7=0
x=-4
x+4=0
If needed you could expand but I'm too lazy
Best Answer:<span> </span><span>So first we need both areas, then we can relate them, and then divide the circle by the square:
A(circle) = πr^2
A(square) = L*W or (2r)*(2r) which is (2r)^2
For the square, we know this is true because because the radius is half the diameter, so if we multiply the radius by 2, we get the length of one side of the square. We also know that the lengths of both sides of the square are the same by definition of a square.
Ratio: (πr^2)/(4r^2) = π/4</span>
Answer:
5x+4y+12z
Step-by-step explanation:
i hope this help
