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Mrac [35]
2 years ago
14

B is the midpoint of a segment AC. AB = 5x, BC = 3x+4 Find x, AB, BC, and AC.

Mathematics
1 answer:
Shalnov [3]2 years ago
5 0

Given below is the answer

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What is the value of the sin3x/6x; as x approaches to zero
nikklg [1K]

Step-by-step explanation:

When x = 0,

sin3x / 6x = 0 / 0, which is an indeterminate form.

Hence we use L'Hospital's rule:

d/dx (sin3x) = 3cos3x

d/dx (6x) = 6

Now we have 3cos3x / 6 or 0.5cos3x.

When x = 0, 0.5cos3x = 0.5(1) = 0.5.

Hence the limit is 0.5.

6 0
3 years ago
One last question, I really need help
kozerog [31]

Answer:

4800 inches

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
In a certain year, the price of gasoline rose by 20% during January, fell by 20% during February, rose by 25% in March, and fell
satela [25.4K]

Using decimal multipliers, it is found that the value of x is of 16.67.

<h3>What is a decimal multiplier?</h3>

Increases of a% or decreases of a% re represented by decimal values, as follows:

  • The equivalent multiplier for an increase of a% is given by: \frac{100 + a}{100}
  • The equivalent multiplier for an decrease of a% is given by: \frac{100 - a}{100}

In this problem:

  • The price at the beginning of January was of a.
  • Increase of 20% in January, hence 1.2a.
  • Decrease of 20% in February, hence 1.2(0.8)a.
  • Increase of 25% in March, hence 1.2(0.8)(1.25)a.
  • Decrease of x% in April, hence 1.2(0.8)(1.25)\left(\frac{100 - x}{100}\right)a

The price of gasoline at the end of April was the same as it had been at the beginning of January, hence:

a =1.2(0.8)(1.25)\left(\frac{100 - x}{100}\right)a

1.2\left(\frac{100 - x}{100}\right) = 1

\left(\frac{100 - x}{100}\right) = \frac{1}{1.2}

\frac{100 - x}{100} = 0.8333

100 - x = 83.33

x = 16.67

The value of x is of 16.67.

To learn more about decimal multipliers, you can take a look at brainly.com/question/24952336

6 0
2 years ago
A dice is rolled 3 times. What is the probability of getting 1 on each roll?
konstantin123 [22]

Answer:

ANSWER IS: 1/18

Step-by-step explanation:

TRUST ME.

8 0
2 years ago
A 10ft by 20ft rectangular swimming pool is surrounded by a walkway of uniform width. If the total area of the walkway is 216ft^
Dmitry [639]

check the picture below.


so, we know the dimensions of the pool, is a 20x10, so its area is simply 200 ft², and we know the walkway is 216 ft², so the whole thing, including pool and walkway is really 200 + 216 ft².


now, as you see in the picture, the dimensions for the combined area is 20+2x and 10+2x, since the walkway is "x" long, therefore,


\bf \stackrel{length}{(20+2x)}\stackrel{width}{(10+2x)}=200+216\implies \stackrel{FOIL}{4x^2+60x+200}=200+216 \\\\\\ 4x^2+60x=216\implies \stackrel{dividing~by~4}{x^2+15x=54} \\\\\\ x^2+15x-54=0\implies (x+18)(x-3)=0\implies x= \begin{cases} -18\\ \boxed{3} \end{cases}


notice, it cannot be -18, since is a positive length unit.

5 0
2 years ago
Read 2 more answers
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