<span>The number of cell phone minutes used by high school seniors follows a normal distribution with a mean of 500 and a standard deviation of 50. what is the probability that a student uses more than 580 minutes?
Given
μ=500
σ=50
X=580
P(x<X)=Z((580-500)/50)=Z(1.6)=0.9452
=>
P(x>X)=1-P(x<X)=1-0.9452=0.0548=5.48%
</span>
Answer:
The correct answer is (x-y)
Step-by-step explanation:
x^2-xy
x(x-y)
Answer:
-2.5
Step-by-step explanation:
25/-10 = -2.5
20/-8 = 2.5
10/-4 = 2.5
-5/2 = 2.5
so the answer is -2.5
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Answer:
$18.88 per hour.
Step-by-step explanation:
We first need to find 18% of $16.
16 * 0.18 = 2.88
The pay rate increases by $2.88.
$16 + $2.88 = $18.88
Hope this helps.
