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nika2105 [10]
3 years ago
13

One example of a chemical change is

Chemistry
2 answers:
ikadub [295]3 years ago
8 0
Baking cookies is a chemical change
ser-zykov [4K]3 years ago
6 0

Answer:

When you burn a paper or cooking food

Explanation:

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What is most misleading about the contour map shown below?
Verizon [17]

Answer: The contour interval is inconsistent.

Explanation: I just too the test and this is the correct answer.

6 0
4 years ago
The empirical formula for a compound is CH2. If n is a whole number, which shows a correct relationship between the molecular fo
GaryK [48]

Answer:

D)subscript of C in molecular formula = n x subscript of C in empirical formula

Explanation:

THIS IS THE COMPLETE QUESTION BELOW;

.The empirical formula for a compound is CH2. If n is a whole number, which shows a correct relationship between the molecular formula and the empirical formula? a)<br /><br /> empirical formula mass / molecular mass = n<br /><br /> B) molecular mass = element mass / empirical formula mass ´ 100<br /><br /> c) subscript of H in empirical formula = 2  subscript of H in molecular formula<br /><br /> D) subscript of C in molecular formula = n  subscript of C in empirical formula<br /><br />

An empirical formula can be regarded as "shorten form" of a molecular formula. Instance of this is

A compounds CH4, C2H8, C4H12... with empirical formula of CH4. In this case a constant "n" represent the difference that exist between empirical formula and molecular formula, "n" which is a whole number, molecular formula is the numerator.

Therefore, subscript of C in molecular formula = n x subscript of C in empirical formula

8 0
3 years ago
How many moles are in a 13.7g block of calcium?
goldenfox [79]
<h3>Answer:</h3>

0.342 mol Ca

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right<u> </u>

<u>Chemistry</u>

<u>Atomic Structure</u>

  • Reading a Periodic Table

<u>Stoichiometry</u>

  • Using Dimensional Analysis
<h3>Explanation:</h3>

<u>Step 1: Define</u>

13.7 g Ca

<u>Step 2: Identify Conversions</u>

Molar Mass of Ca - 40.08 g/mol

<u>Step 3: Convert</u>

  1. Set up:                               \displaystyle 13.7 \ g \ Ca(\frac{1 \ mol \ Ca}{40.08 \ g \ Ca})
  2. Multiply/Divide:                 \displaystyle 0.341816 \ mol \ Ca

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 3 sig figs.</em>

0.341816 mol Ca ≈ 0.342 mol Ca

6 0
3 years ago
At a certain temperature, 0.900 mol SO 3 is placed in a 2.00 L container. 2 SO 3 ( g ) − ⇀ ↽ − 2 SO 2 ( g ) + O 2 ( g ) At equil
puteri [66]

Answer: The value of K_c is 0.0057

Explanation:

Initial moles of  SO_3 = 0.900 mole

Volume of container = 2.00 L

Initial concentration of SO_3=\frac{moles}{volume}=\frac{0.900moles}{2.00L}=0.450M  

equilibrium concentration of O_2=\frac{moles}{volume}=\frac{0.110mole}{2.00L}=0.055M [/tex]

The given balanced equilibrium reaction is,

                            2SO_3(g)\rightleftharpoons 2SO_2(g)+O_2(g)

Initial conc.              0.450 M               0        0

At eqm. conc.    (0.450 -2x) M         (2x) M   (x) M

The expression for equilibrium constant for this reaction will be,

K_c=\frac{[O_2][SO_2]^2}{[SO_3]^2}

K_c=\frac{x\times (2x)^2}{0.450-2x)^2}

we are given : x = 0.055

Now put all the given values in this expression, we get :

K_c=\frac{0.055\times (2\times 0.055)^2}{0.450-2\times 0.055)^2}

K_c=0.0057

Thus the value of the equilibrium constant is 0.0057

3 0
4 years ago
What are the most common petrochemical products and their uses?
Rashid [163]
Petrochemicals are separated into 3 groups: Olefins, Aromatics, and Synthesis Gas.

Olefins: Ethelyne (Plastic Products), Propelyne (Plastic Products), and Butadiene (Synthetic Rubber)
Aromatics: Benzene (Dyes), Toluene (Polyurethane), and Xylenes (Synthetic Fibers)
Synthesis Gas: Ammonia (Fertilizer Urea) and Methanol (Chemical intermediate)
7 0
4 years ago
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