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3 years ago

One example of a chemical change is

Chemistry

2 answers:

ikadub [295]3 years ago

8 0

Baking cookies is a chemical change

ser-zykov [4K]3 years ago

6 0

Answer:

When you burn a paper or cooking food

Explanation:

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What is most misleading about the contour map shown below?

Verizon [17]

Answer: The contour interval is inconsistent.

Explanation: I just too the test and this is the correct answer.

6 0

4 years ago

The empirical formula for a compound is CH2. If n is a whole number, which shows a correct relationship between the molecular fo

GaryK [48]

Answer:

D)subscript of C in molecular formula = n x subscript of C in empirical formula

Explanation:

THIS IS THE COMPLETE QUESTION BELOW;

.The empirical formula for a compound is CH2. If n is a whole number, which shows a correct relationship between the molecular formula and the empirical formula? a) empirical formula mass / molecular mass = n B) molecular mass = element mass / empirical formula mass ´ 100 c) subscript of H in empirical formula = 2 subscript of H in molecular formula D) subscript of C in molecular formula = n subscript of C in empirical formula

An empirical formula can be regarded as "shorten form" of a molecular formula. Instance of this is

A compounds CH4, C2H8, C4H12... with empirical formula of CH4. In this case a constant "n" represent the difference that exist between empirical formula and molecular formula, "n" which is a whole number, molecular formula is the numerator.

Therefore, subscript of C in molecular formula = n x subscript of C in empirical formula

8 0

3 years ago

How many moles are in a 13.7g block of calcium?

goldenfox [79]

<h3>Answer:</h3>

0.342 mol Ca

<h3>General Formulas and Concepts:</h3>

Math

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Chemistry

Atomic Structure

Reading a Periodic Table

Stoichiometry

Using Dimensional Analysis

<h3>Explanation:</h3>

Step 1: Define

13.7 g Ca

Step 2: Identify Conversions

Molar Mass of Ca - 40.08 g/mol

Step 3: Convert

Set up: $\displaystyle 13.7 \ g \ Ca(\frac{1 \ mol \ Ca}{40.08 \ g \ Ca})$
Multiply/Divide: $\displaystyle 0.341816 \ mol \ Ca$

Step 4: Check

Follow sig fig rules and round. We are given 3 sig figs.

0.341816 mol Ca ≈ 0.342 mol Ca

6 0

3 years ago

At a certain temperature, 0.900 mol SO 3 is placed in a 2.00 L container. 2 SO 3 ( g ) − ⇀ ↽ − 2 SO 2 ( g ) + O 2 ( g ) At equil

puteri [66]

Answer: The value of $K_c$ is 0.0057

Explanation:

Initial moles of $SO_3$ = 0.900 mole

Volume of container = 2.00 L

Initial concentration of $SO_3=\frac{moles}{volume}=\frac{0.900moles}{2.00L}=0.450M$

equilibrium concentration of $O_2=\frac{moles}{volume}=\frac{0.110mole}{2.00L}=0.055M$ [/tex]

The given balanced equilibrium reaction is,

$2SO_3(g)\rightleftharpoons 2SO_2(g)+O_2(g)$

Initial conc. 0.450 M 0 0

At eqm. conc. (0.450 -2x) M (2x) M (x) M

The expression for equilibrium constant for this reaction will be,

$K_c=\frac{[O_2][SO_2]^2}{[SO_3]^2}$

$K_c=\frac{x\times (2x)^2}{0.450-2x)^2}$

we are given : x = 0.055

Now put all the given values in this expression, we get :

$K_c=\frac{0.055\times (2\times 0.055)^2}{0.450-2\times 0.055)^2}$

$K_c=0.0057$

Thus the value of the equilibrium constant is 0.0057

3 0

4 years ago

What are the most common petrochemical products and their uses?

Rashid [163]

Petrochemicals are separated into 3 groups: Olefins, Aromatics, and Synthesis Gas.

Olefins: Ethelyne (Plastic Products), Propelyne (Plastic Products), and Butadiene (Synthetic Rubber)
Aromatics: Benzene (Dyes), Toluene (Polyurethane), and Xylenes (Synthetic Fibers)
Synthesis Gas: Ammonia (Fertilizer Urea) and Methanol (Chemical intermediate)

7 0

4 years ago