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Sergeeva-Olga [200]
3 years ago
8

What is the variable for the quantity of heat in a system?

Chemistry
1 answer:
Crank3 years ago
8 0

Answer:

The heat capacity is the amount of heat, expressed usually in Joules or calories, needed to change the system by 1 degree Celsius. The specific heat capacity is the amount of heat required to raise 1 gram of a substance by 1 degree Celsius.

Explanation:

For example, the specific heat of H2O(l) is 4.18 J/g ° C.

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Nvmmmmmmmmmmmmmmmmmmmmmmmmm lol
Vlad1618 [11]

Answer:

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Explanation:

7 0
3 years ago
Read 2 more answers
write a generalization correlating solubility with ionization. start with: "as compounds become more ionized,..."
Tema [17]

Answer:

the solubility increases

Explanation:

The solubility of any ionic compound is due to the ionization of the compound and then the strong ion-dipole interactions acting between the ions and the solvent.

Thus, solubility also depends on the extent of the ionization of the salt.

The more the salt ionizes, the more there is ion-dipole interaction between the ions the solvent and more is the solubility.

4 0
2 years ago
The column just before the stable noble gases are called the
Sergio039 [100]
Is called the Halogen
6 0
2 years ago
He isotope 62(over28ni has the largest binding energy per nucleon of any isotope. calculate this value from the atomic mass of n
irina [24]
The atomic mass of the isotope Ni ( 62 over 28 ) = 61.928345 amu.
Mass of the electrons: 28 · 5.4584 · 10^(-4 ) amu = 0.0152838 amu ( g/mol )
Mass of the nuclei:
61.928345 amu - 0.0152838 amu = 61.913062 amu (g/mol)
The mass difference between a nucleus and its constituent nucleons is called the mass defect.
For Ni ( 62 over 28 ): Mass of the protons: 28 · 1.00728 amu = 28.20384 amu
Mass of the neutrons: 34 · 1.00866 amu = 34.299444 amu
In total : 62.49828 amu
The mass defect = 62.49828 - 61.913062 = 0.585218 amu
Nucleus binding energy:
E = Δm · c² ( the Einstein relationship )
E = 0.585218 · ( 2.9979 · 10^8 m/s )² · 1 / (6.022 · 10^23) · 1 kg / 1000 g =
= 0.585218 · 8.9874044 · 10 ^16 : (6.022 · 10^23) · 0.001 =
= ( 5.2595908 : 6.022 ) · 0.001 · 10^(-7 ) =
= 0.0008733 · 10^(-7) J = 8.733 · 10^(-11) J
The nucleus binding energy per nucleon:
8.733 · 10^(-11) J : 62 =  0.14085 · 10 ^(-11) =
= 1.4085 · 10^(-12) J per nucleon.
4 0
3 years ago
Determine how many millilitres of a 4.25 M HCl solution are needed to react completely with 8.75 g CaCO3?
Helen [10]

Answer:

41 mL

Explanation:

Given data:

Milliliter of HCl required = ?

Molarity of HCl solution = 4.25 M

Mass of CaCO₃ = 8.75 g

Solution:

Chemical equation:

2HCl + CaCO₃      →    CaCl₂ + CO₂ + H₂O

Number of moles of CaCO₃:

Number of moles = mass/molar mass

Number of moles = 8.75 g / 100.1 g/mol

Number of moles = 0.087 g /mol

Now we will compare the moles of  CaCO₃ with HCl.

                      CaCO₃         :          HCl

                          1               :            2

                      0.087           :         2/1×0.087 = 0.174 mol

Volume of HCl:

Molarity = number of moles / volume in L

4.25 M = 0.174 mol / volume in L

Volume in L = 0.174 mol /4.25 M

Volume in L = 0.041 L

Volume in mL:

0.041 L×1000 mL/ 1L

41 mL

8 0
2 years ago
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