Would you rather prove a quadrilateral is a parallelogram by using slopes or lengths?
1 answer:
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You basically plug in the x values with the given function so the y values are -5,-10,-15,-20
Solution: The sequence B shows the steeper line.
Exanation:
The line having greater slope is always steeper than the other lines.
Since it is given that the sequence A increases by 3 and the sequence B increases by 8. It means for each additional value the sequences increased by 3 and 5 units respectively.
The slope of line is rate of change of one variable with respect to another variable.
The sequence A increased by 3, therefore the slope of line of sequence A is 3.
The sequence B increased by 8, therefore the slope of line of sequence B is 8.
Since the slope of sequence B is greater than the slope of sequence A, therefore the line of sequence B is steeper than the line of sequence A.
The sequence A can be defined as 3,6,9,12,.... and the sequence B can be defined as 8,16,24,....
So the coordinates points of sequence A are (0,0)(1,3),(2,6) and the coordinates points of sequence B are (0,0),(1,8),(2,16).
From the given figure it is notes that the blue line is steeper than red line.
Therefore, the sequence B shows the steeper line.
