3 years ago

Can someone please help me with these two questions

Mathematics

2 answers:

lara31 [8.8K]3 years ago

5 0

The answer is X=6,-6 u just have to foil it out (X-6)(x+6)=0 X-6=0 X+6=0 X=6,-6

Eva8 [605]3 years ago

4 0

The # 1 the answer is A
# 2 C

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3 years ago

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Answer:

$\sqrt[3]{\left(-0.05\right)^{24}}=0.05^8$

so option D is correct.

Step-by-step explanation:

Given the expression

$\sqrt[3]{\left(-0.05\right)^{24}}$

$\mathrm{Apply\:radical\:rule}:\quad \sqrt[n]{a}=a^{\frac{1}{n}}$

$\sqrt[3]{\left(-0.05\right)^{24}}=\left(\left(-0.05\right)^{24}\right)^{\frac{1}{3}}$

$\mathrm{Apply\:exponent\:rule}:\quad \left(a^b\right)^c=a^{bc}$

$=\left(-0.05\right)^{24\cdot \frac{1}{3}}$

$=\left(-0.05\right)^8$

$\mathrm{Apply\:exponent\:rule}:\quad \left(-a\right)^n=a^n,\:\mathrm{if\:}n\mathrm{\:is\:even}$

$=0.05^8$

Hence, the simplification will be:

$\sqrt[3]{\left(-0.05\right)^{24}}=0.05^8$

Therefore, option D is correct.

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3 years ago