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3 years ago

Can someone please help me with these two questions

Mathematics

2 answers:

lara31 [8.8K]3 years ago

5 0

The answer is X=6,-6 u just have to foil it out (X-6)(x+6)=0 X-6=0 X+6=0 X=6,-6

Eva8 [605]3 years ago

4 0

The # 1 the answer is A
# 2 C

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The area of a playground is 12 square yards. The length of the playground is 3 times longer than its width. Find the length and

marishachu [46]

Answer:

Width is 2 and Length is 6

Step-by-step explanation:

As the data is given, the area of a playground is 12 square yards.
The length of the playground is 3 times longer than its width.
Let width is x, length is 3 times therefore, length = 3x

As we know the formula for area,

Area=length x width.

So by putting values in this formula,

12sq = (3x)(x)

=> 3x2 = 12

=> x2 = 12/3,

=> x2 = 4 ,

by taking square root we get x= 2,

the width is 2 and length is 3 times hence, length is 3(2) = 6.

6 0

3 years ago

1 + 1 - 1 = ? For fun- .........

coldgirl [10]

Answer:

1+1=2-1=1

Step-by-step explanation:

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8 0

2 years ago

Read 2 more answers

Solve the following using Substitution method 2x – 5y = -13 3x + 4y = 15

Digiron [165]

$\huge \boxed{\mathfrak{Question} \downarrow}$

Solve the following using Substitution method

2x – 5y = -13

3x + 4y = 15

$\large \boxed{\mathfrak{Answer \: with \: Explanation} \downarrow}$

$\left. \begin{array} { l } { 2 x - 5 y = - 13 } \\ { 3 x + 4 y = 15 } \end{array} \right.$

To solve a pair of equations using substitution, first solve one of the equations for one of the variables. Then substitute the result for that variable in the other equation.

$2x-5y=-13, \: 3x+4y=15$

Choose one of the equations and solve it for x by isolating x on the left-hand side of the equal sign. I'm choosing the 1st equation for now.

$2x-5y=-13$

Add 5y to both sides of the equation.

$2x=5y-13$

Divide both sides by 2.

$x=\frac{1}{2}\left(5y-13\right) \\$

Multiply $\frac{1}{2}\\$ times 5y - 13.

$x=\frac{5}{2}y-\frac{13}{2} \\$

Substitute $\frac{5y-13}{2}\\$ for x in the other equation, 3x + 4y = 15.

$3\left(\frac{5}{2}y-\frac{13}{2}\right)+4y=15 \\$

Multiply 3 times $\frac{5y-13}{2}\\$ .

$\frac{15}{2}y-\frac{39}{2}+4y=15 \\$

Add $\frac{15y}{2} \\$ to 4y.

$\frac{23}{2}y-\frac{39}{2}=15 \\$

Add $\frac{39}{2}\\$ to both sides of the equation.

$\frac{23}{2}y=\frac{69}{2} \\$

Divide both sides of the equation by 23/2, which is the same as multiplying both sides by the reciprocal of the fraction.

$\large \underline{ \underline{ \sf \: y=3 }}$

Substitute 3 for y in $x=\frac{5}{2}y-\frac{13}{2}\\$ . Because the resulting equation contains only one variable, you can solve for x directly.

$x=\frac{5}{2}\times 3-\frac{13}{2} \\$

Multiply 5/2 times 3.

$x=\frac{15-13}{2} \\$

Add $-\frac{13}{2}\\$ to $\frac{15}{2}\\$ by finding a common denominator and adding the numerators. Then reduce the fraction to its lowest terms if possible.

$\large\underline{ \underline{ \sf \: x=1 }}$

The system is now solved. The value of x & y will be 1 & 3 respectively.

$\huge\boxed{ \boxed{\bf \: x=1, \: y=3 }}$

8 0

2 years ago

Estelle is raking leaves in her yard. After 1 hour, she has 2 bags of leaves. After 3 hours, she has 6 bags of leaves. Which gra

denis-greek [22]

The graph with the line going through (0,0) with a slope of 2. This is because for every 1 hour, she has 2 bags of leaves.
The y number goes up by 2. 0 hours, 0 bags. 1 hour, 2 bags. 2 hours, 4 bags. And so on.
(0,0), (1,2), (2,4), (3,6)...

7 0

3 years ago

Can someone help me figure out the answer to: 3 5/8 + 4 2/3? (please explain working?)

ivanzaharov [21]

You would first make the fractions improper (making the numerator bigger then the denominator) in order to do that times the denominator with the whole number and add the numerator.
Ex) 3*8 = 24 + 5 = 29/8
Then you would add both of the improper fractions

3 0

3 years ago