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3 years ago

Please help! i do not understand !

Mathematics

2 answers:

labwork [276]3 years ago

7 0

The answer would be
C) 3x+20+2x=180

cluponka [151]3 years ago

3 0

Answer:

Step-by-step explanation:

Know that two angles added equals 180

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1. Draw a diagram that will help you explain why sin(0) = cos(90 – 6).

BARSIC [14]

Answer:

Use https://www.bartleby.com/ it has helped me out a lot . Its actual tutors/teachers who answer your questions in about 30 minutes :)

Step-by-step explanation:

8 0

3 years ago

Find the volume V of the solid obtained by rotating the region bounded by the given curves about the specified line. Y = (4/9) x

frez [133]

Answer:

V = 8.06 cubed units

Step-by-step explanation:

You have the following curves:

$y_1=\frac{4}{9}x^2=f(x)\\\\y_2=\frac{13}{9}-x^2=g(x)$

In order to calculate the solid of revolution bounded by the previous curves and the x axis, you use the following formula:

$V=\pi \int_a^b [(g(x))^2-(f(x))^2]dx$ (1)

To determine the limits of the integral you equal both curves f=g and solve for x:

$f(x)=g(x)\\\\\frac{4}{9}x^2=\frac{13}{9}-x^2\\\\\frac{4}{9}x^2+x^2=\frac{13}{9}\\\\\frac{13}{9}x^2=\frac{13}{9}\\\\x=\pm 1$

Then, the limits are a = -1 and b = 1

You replace f(x), g(x), a and b in the equation (1):

$V=\pi \int_{-1}^{1}[(\frac{13}{9}-x^2)^2-(\frac{4}{9}x^2)^2]dx\\\\V=\pi \int_{-1}^1[\frac{169}{81}-\frac{26}{9}x^2+x^4-\frac{16}{81}x^4]dx\\\\V=\pi \int_{-1}^1 [\frac{169}{81}-\frac{26}{9}x^2+\frac{65}{81}x^4]dx\\\\V=\pi [\frac{169}{81}x-\frac{26}{27}x^3+\frac{65}{405}x^5]_{-1}^1\\\\V\approx8.06\ cubed\ units$

The volume of the solid of revolution is approximately 8.06 cubed units

8 0

3 years ago

Jack is mowing a lawn that has a shed. needs to know area of lawn to mow. dimensions of yard are 5x by 13 x-4 . she'd are 2x by

Elena-2011 [213]

The diagram of the lawn and the shed is shown below.

The area of the lawn needed to be mowed equals to the area of the yard minus the area of the shed

The area of the yard = $(5x)(13x-4) = 65 x^{2} -20x$
The area of the shed = $(2x)(2x+4)=4 x^{2} +8x$

The area of the lawn = $65 x^{2} -20x-(4 x^{2} +8x)$
The area of the lawn = $65 x^{2} -20x-4 x^{2} -8x$
The area of the lawn = $61 x^{2} -28x$

5 0

3 years ago

A phone originally cost £70 and is increased to £77<br> What is the percentage increase?

andre [41]

Answer:

mark me brainliest

Step-by-step explanation:

10% increased

6 0

3 years ago

Read 2 more answers

Evaluating more integrals

Greeley [361]

(a) The integral is equal to the area of the triangle; it has height 20 and base 10, so the area is 20*10/2 = 100.

(b) The integral is equal to the area of the semicircle with radius 10. It's also under the horizontal axis, so the area is negative. The semicircle has area $\frac{\pi10^2}2=50\pi$ , so the integral is -50π.

$\displaystyle\int_{30}^{35}g(x)\,\mathrm dx$

which is the area of the triangle on the right. It has height and base 5, so its area is 25/2.

Then split up the desired integral as

$\displaystyle\int_0^{35}g(x)\,\mathrm dx=\int_0^{10}g(x)\,\mathrm dx+\int_{10}^{30}g(x)\,\mathrm dx+\int_{30}^{35}g(x)\,\mathrm dx$

and plug in the integral values you know:

$\displaystyle\int_0^{35}g(x)\,\mathrm dx=100-50\pi+\frac{25}2=\frac{225}2-50\pi$

4 0

3 years ago