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artcher [175]
3 years ago
12

HERE ARE TWO NUMBER MACHINES A AND B

Mathematics
1 answer:
nika2105 [10]3 years ago
5 0

Answer:

x=-7

Step-by-step explanation:

We can write them both like functions like this

A=5x-4

B=3x+8

Where

x=input

A=Output A

B=Output B

We want the output of A 3 times the output of B this can be written like this:

A=3B

we replace with the functions

5x-4=3(3x+8)

we solve for x

5x-4=9x+24\\5x-9x=24+4\\-4x=28\\x=\frac{28}{-4}\\x=-7

The output that makes the out put of A 3 times teh output of B is -7

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Answer:

The expected value of playing the game is $0.75.

Step-by-step explanation:

The expected value of a random variable is the weighted average of the random variable.

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E(X)=\sum x\cdot P(X=x)

The random variable <em>X</em> in this case can be defined as the amount won in playing the game.

The probability distribution of <em>X</em> is as follows:

Number on spinner:   1           2           3          4           5              6

Amount earned (<em>X</em>):   $1        $4         $7        $10     -$8.75     -$8.75

Probability:                 1/6       1/6         1/6        1/6         1/6           1/6

Compute the expected value of <em>X</em> as follows:

E(X)=\sum x\cdot P(X=x)

         =(1\times \frac{1}{6})+(4\times \frac{1}{6})+(7\times \frac{1}{6})+(10\times \frac{1}{6})+(-8.75\times \frac{1}{6})+(-8.75\times \frac{1}{6})

         =\frac{1}{6}+\frac{4}{6}+\frac{7}{6}+\frac{10}{6}-\frac{8.75}{6}-\frac{8.75}{6}

         =\frac{1+4+7+10-8.75-8.75}{6}

         =0.75

Thus, the expected value of playing the game is $0.75.

5 0
3 years ago
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