Answer:
20.4g
Explanation:
First, we need to write a balanced equation for the reaction of butane to produce carbon dioxide.
When butane undergo Combustion, it will produce carbon dioxide and water as shown below:
2C4H10 + 13O2 —> 8CO2 + 10H2O
Molar Mass of C4H10 = (12x4) + (10x1) = 48 + 10 = 58g/mol
Mass of C4H10 from the balanced equation = 2 x 58 = 116g
Molar Mass of CO2 = 12 + (2x16) = 12 + 32 = 44g/mol
Mass of CO2 from the balanced equation = 8 x 44 = 352g
From the equation,
116g of C4H10 produced 352g of CO2.
Therefore, Xg of C4H10 will produce 61.9g of CO2 i.e
Xg of C4H10 = (61.9 x 116)/352 = 20.4g
Therefore, 20.4g of butane(C4H10) is needed to produce 61.9g of CO2
Answer:
Explanation:
Raoult's law is a tool that allows to determine vapour pressure of solutions. The formula is:
<em>(1)</em>
Where
P is Pressure of solution and solvent and X is mole fraction.
Moles of solute and solvent are:
Biphenyl:
11.5g×(1mol /154.21g) = <em>0.0746mol</em>
Benzene
31.9g×(1mol /78.11g) = <em>0.408mol</em>
Mole fraction of benzene is:
= <em>0.846</em>
Replacing in (1):


I hope it helps!
It should be A
But you have this as chemistry? I think this is like a biology question
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