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Thepotemich [5.8K]
3 years ago
14

Help! help! plz............

Chemistry
1 answer:
zhuklara [117]3 years ago
8 0
There the picture is the answer from the internet

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How much of a 50g sample of 85Kr will remain after 2 half-lives?
Rashid [163]

Answer:

i need help with my work

Explanation:

8 0
3 years ago
Question 20 (1 point)
romanna [79]

Answer:

A. The ratio of the element in glucose is different than in ethanol

Explanation:

The compounds given are;

      Glucose      C₆H₁₂O₆

     Ethanol         C₂H₆O

The two compounds given are different from one another. But they have the same elemental composition.

   Ethanol is made up of Carbon, hydrogen and Oxygen and so also, Glucose

Now,

  The number of atoms in both compounds are different;

                                   Number of atoms

                        C                             H                     O

Glucose           6                             12                      6

Ethanol            2                              6                       1

8 0
3 years ago
HElPpp AsAPp I’ll mark you as brainlister!!
vichka [17]
A. There is no extra information
5 0
3 years ago
How do the numbers of metal and non-metal elements compare? Estimate an approximate percentage difference.
Lerok [7]

Answer:

metal to non metal ratio is 97/21 = 4.62 or

82.2% metals, 17.8% non metals

Explanation:

How do the numbers of metal and non-metal elements compare? Estimate an approximate percentage difference. (learning about the periodic table if...

of 118 elements in the periodic table , 21 are non metals (even H has metallic properties when approching 0 degrees K)

this means there ar 21 nonmetals and 118-21=97 metals.

6 0
2 years ago
Some one help me please I'm stuck Show using two conversion factors how you would convert from 0.020 kg into mg.
julia-pushkina [17]

Answer:

=2.0x10^4mg

Explanation:

Hello there!

In this case, when performing units conversions involving two proportional factors we need to make sure we first convert to the base unit and then to the target one; thus, since 1 kg = 1000 g and 1 g = 1000 mg, we set up the following expression:

=0.020kg*\frac{1000g}{1kg} *\frac{1000mg}{1g} \\\\=2.0x10^4mg

Best regards!

4 0
3 years ago
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