Explanation:
Molar mass of
= 39.1 + 35.5 + 3(16.0) = 122.6 g
Molar mass of KCl = 39.1 + 35.5 = 74.6 g
Molar mass of
= 32.0 g
According to the equation, 2 moles of
reacts to give 3 moles of oxygen.
Therefore, 2 (122.6) = 245.2 g of
will give 3 (32.0) = 96.0 g of oxygen. Thus, 245.2 g of
gives 96.0 g of oxygen.
(a) Calculate the amount of oxygen given by 2.72 g of
as follows.
of
(b) Calculate the amount of oxygen given by 0.361 g of
as follows.
of
c) Calculate the amount of oxygen given by 83.6 kg
as follows.
of ![O_{2}](https://tex.z-dn.net/?f=O_%7B2%7D)
Convert kg into grams as follows.
= 32731 g of ![O_{2}](https://tex.z-dn.net/?f=O_%7B2%7D)
(d) Calculate the amount of oxygen given by 22.5 mg of
as follows.
![\frac {96g}{245.2g} \times 22.5 mg = 8.79 mg](https://tex.z-dn.net/?f=%5Cfrac%20%7B96g%7D%7B245.2g%7D%20%5Ctimes%2022.5%20mg%20%3D%208.79%20mg)
Convert mg into grams as follows.
of ![O_{2}](https://tex.z-dn.net/?f=O_%7B2%7D)
Answer:
Yes
Explanation:
The virtue that tungsten is metal it means that it does conduct electricity. Tungsten does conduct electricity currents quite well, such as when compared to iron and nickel. It is, however, not a good conductor as compared to other metals though it does get the job done.
Answer: The new concentration of a solution of
is 0.2 M 10.0 mL of a 2.0 M
solution is diluted to 100 mL.
Explanation:
Given:
= 10.0 mL,
= 2.0 M
= 100 mL,
= ?
Formula used to calculate the new concentration is as follows.
![M_{1}V_{1} = M_{2}V_{2}](https://tex.z-dn.net/?f=M_%7B1%7DV_%7B1%7D%20%3D%20M_%7B2%7DV_%7B2%7D)
Substitute the values into above formula as follows.
![M_{1}V_{1} = M_{2}V_{2}\\10.0 mL \times 2.0 M = M_{2} \times 100 mL\\M_{2} = 0.2 M](https://tex.z-dn.net/?f=M_%7B1%7DV_%7B1%7D%20%3D%20M_%7B2%7DV_%7B2%7D%5C%5C10.0%20mL%20%5Ctimes%202.0%20M%20%3D%20M_%7B2%7D%20%5Ctimes%20100%20mL%5C%5CM_%7B2%7D%20%3D%200.2%20M)
Thus, we can conclude that the new concentration of a solution of
is 0.2 M 10.0 mL of a 2.0 M
solution is diluted to 100 mL.
Hahahaaaa none of the above but IF <span>(c) is
1/2 mole of NaCl and 1/3 mole of MgCl2 instead,
then C is the right ans :)</span>
Hey there!:
From the given data ;
Reaction volume = 1 mL , enzyme content = 10 ug ( 5 ug in 2 mg/mL )
Enzyme mol Wt = 45,000 , therefore [E]t is 10 ug/mL , this need to be express as "M" So:
[E]t in molar = g/L * mol/g
[E]t = 0.01 g/L * 1 / 45,000
[E]t = 2.22*10⁻⁷
Vmax = 0.758 umole/min/ per mL
= 758 mmole/L/min
=758000 mole/L/min => 758000 M
Therefore :
Kcat = Vmax/ [E]t
Kcat = 758000 / 2.2*10⁻⁷ M
Kcat = 3.41441 *10¹² / min
Kcat = 3.41441*10¹² / 60 per sec
Kcat = 5.7*10¹⁰ s⁻¹
Hence kcat of xyzase is 5.7*10¹⁰ s⁻¹
Hope that helps!