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Vlad1618 [11]
3 years ago
6

Morphine has the formula c17h19no3. it is a base and accepts one proton per molecule. it is isolated from opium. a 0.685 −g samp

le of opium is found to require 8.91 ml of a 1.16×10−2 m solution of sulfuric acid for neutralization. part a assuming that morphine is the only acid or base present in opium, calculate the percent morphine in the sample of opium.
Chemistry
1 answer:
kotykmax [81]3 years ago
7 0
2 C₁₇H₁₉NO₃ + H₂SO₄ → Product
Moles of H₂SO₄ = M x V(liters) = 0.0116 x 8.91/1000 = 1.033 x 10⁻⁴ mole 
moles of morphine = 2 x moles of H₂SO₄ = 2.066 x 10⁻⁴
Mass of morphine = moles x molar mass of morphine = 2.066 x 10⁻⁴ x 285.34 
                             = 0.059 g
percent morphine = \frac{mass of morphine}{mass of opium} x 100
                             = \frac{0.059}{0.685} x 100 = 8.6 %   
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