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Vlad1618 [11]
3 years ago
6

Morphine has the formula c17h19no3. it is a base and accepts one proton per molecule. it is isolated from opium. a 0.685 −g samp

le of opium is found to require 8.91 ml of a 1.16×10−2 m solution of sulfuric acid for neutralization. part a assuming that morphine is the only acid or base present in opium, calculate the percent morphine in the sample of opium.
Chemistry
1 answer:
kotykmax [81]3 years ago
7 0
2 C₁₇H₁₉NO₃ + H₂SO₄ → Product
Moles of H₂SO₄ = M x V(liters) = 0.0116 x 8.91/1000 = 1.033 x 10⁻⁴ mole 
moles of morphine = 2 x moles of H₂SO₄ = 2.066 x 10⁻⁴
Mass of morphine = moles x molar mass of morphine = 2.066 x 10⁻⁴ x 285.34 
                             = 0.059 g
percent morphine = \frac{mass of morphine}{mass of opium} x 100
                             = \frac{0.059}{0.685} x 100 = 8.6 %   
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The law of conservation has been stated that the mass and energy has neither be created nor destroyed in a chemical reaction.

The law of conservation has been evident when there has been an equal number of atoms of each element in the chemical reaction.

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The given equation has been assessed as follows:

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The reactant has absence of hydrogen, while hydrogen has been present in the product. Thus, the reaction will not follow the law of conservation.

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The value of log₂(x/4) is 22. Using the properties of the logarithm, the required value is calculated.

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The required logarithm properties are

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It is given that,

log₄(x) = 12;

On applying the property logₐx = n ⇒ aⁿ = x; here a = 4;

So,

log₄(x) = 12 ⇒ 4¹² = x

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Then, calculating log₂(x/4):

log₂(x/4) = log₂(2²⁴/4)

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              = log₂(2²⁴ ⁻ ²)

              = log₂(2²²)

On applying the property logₐ(xⁿ) = n logₐ(x);

log₂(x/4) = 22 log₂2

We know that logₐa = 1;

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A galvanic cell is an electrochemical device that transforms chemically generated free energy into electrical energy. A photogalvanic cell produces photochemical species that react to produce an electrical current when connected to an external circuit.

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In order to create a pathway for the flow of electrons via this wire, the galvanic cell makes use of the ability to split the flow of electrons during the processes of oxidation and reduction, forcing a half-reaction and linking each with a wire.

An electrochemical device known as a galvanic cell converts chemical energy from a spontaneous redox response into electrical energy. It possesses an electrical potential of 1.1 V. The anode, which is a negative plate in galvanic cells, is where oxidation takes place. It is a positive plate where lessening takes place.

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