Please Solve this! I need help
1 answer:
Answer:
To plot a graph, you put the independent variable on the y-axis and the dependent on the x-axis. This might sound really hard, but it's not.
A dependent variable is something that is changed by other factors. For example, in this question, the temperature is dependent on the time. You can't change time by temperature, it's impossible. But you CAN change temperature by the more time that goes by. This makes Time independent and Temperature Independent.
You write the graph so that Time (1-10) goes up the side (the y-axis), starting from the bottom left (this point is called the origin). Then you write the Temperature on the bottom, from left to right. The numbers you are given have to have the same amount of points (the little squares you see) in between them, and you have to be able to fit all of the numbers on the graph.
The last step is to plot the points on the graph so they match up. If the time is 1, then you go to where the time says one and move over to the right to where it is the correct temperature. That is where you put your point. You keep doing this until you have all the points plotted and you can connect the dots.
Explanation:
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Answer:
See figure 1
Explanation:
We have to remember that in the isomer structures we have to <u>change the structure</u> but we have to maintain the <u>same formula</u>, in this case .
In the formula, we have 1 nitrogen atom. Therefore we will have as a main functional group the <u>amine group</u>.
In the amines, we have different types of amines. Depending on the number of carbons bonded to the "N" atom. In the <em>primary amines</em>, we have only 1 C-H. In the <em>secondary amines</em>, we have two C-N bonds and in the <em>tertiary amines</em>, we have three C-N bonds.
With this in mind, we can have:
-) <u>Primary amines:</u>
1) n-butyl amine
2) sec-butyl amine including 2 optical isomers
3) isobutyl amine
4) tert-butyl amine
-) <u>Secondary amines:</u>
5) N-methyl n-propyl amine
6) N-methyl isopropyl amine
7) N, N-diethyl amine
-) <u>Tertiary amines:</u>
8) N-ethyl N, N-dimethyl amine
See figure 1
I hope it helps!
Answer: -
12.41 g
Explanation: -
Mass of CO₂ = 42 g
Molar mass of CO₂ = 12 x 1 + 16 x 2 = 44 g / mol
Number of moles of CO₂ =
= 0.9545 mol
The balanced chemical equation for this process is
2C₆H₆ + 15O₂ → 12CO₂ + 6H₂O
From the balanced chemical equation we see
12 mol of CO₂ is produced from 2 mol of C₆H₆
0.9545 mol of CO₂ is produced from
= 0.159 mol of C₆H₆
Molar mass of C₆H₆ = 12 x 6 + 1 x 6 =78 g /mol
Mass of C₆H₆ =Molar mass x Number of moles
= 78 g / mol x 0.159 mol
= 12.41 g