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3 years ago

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At medina middle school 2% of the students ride bikes to school. If 950 students attend Medina middle school how many students r

ide a bike to school?

1 answer:

svet-max [94.6K]3 years ago

8 0

19 students. 950 times 0.02= 19

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Mathematics need help hurry and wander this question ** picture involved**

ser-zykov [4K]

Answer:

radius = 15ft

diameter = 30ft

Step-by-step explanation:

7 0

3 years ago

In your own words, explain why there is no solution to the following equation:| x-6|= -8 Also, knowing this, how does it help to

solniwko [45]

Answer:

Step-by-step explanation:

So the two lines before and after the expression means absolute value, or modulus of, knowing this, it means that the answer must always yield positive. So if x-6 is positive, it will stay positive, if x-6 is negative, it will turn positive, therefore it can never yield a negative value.

Now im assuming the second question is meant to be absolute value of x-5 is less than 0, because it makes no sense otherwise.

So now knowing that x-5 is always positive, or 0, but this inequality only wants less than 0, this means there are no solutions for the inequality.

5 0

3 years ago

CaHeK987 [17]

Since q(x) is inside p(x), find the x-value that results in q(x) = 1/4

$\frac{1}{4} = 5 - x^2\ \Rightarrow\ x^2 = 5 - \frac{1}{4}\ \Rightarrow\ x^2 = \frac{19}{4}\ \Rightarrow \\
x = \frac{\sqrt{19} }{2}$

so we conclude that
$q(\frac{\sqrt{19} }{2} ) = 1/4$

therefore

$p(1/4) = p\left( q\left(\frac{ \sqrt{19} }{2} \right) \right)$

plug $x=\sqrt{19}/2$ into p( q(x) ) to get answer

$p(1/4) = p\left( q\left( \frac{ \sqrt{19} }{2} \right) \right)\ \Rightarrow\ \dfrac{4 - \left( \frac{\sqrt{19} }{2}\right)^2 }{ \left( \frac{\sqrt{19} }{2}\right)^3 } \Rightarrow \\ \\ \dfrac{4 - \frac{19}{4} }{ \frac{19\sqrt{19} }{8}} \Rightarrow \dfrac{8\left(4 - \frac{19}{4}\right) }{ 8 \cdot \frac{19\sqrt{19} }{8}} \Rightarrow \dfrac{32 - 38}{19\sqrt{19}} \Rightarrow \dfrac{-6}{19\sqrt{19}} \cdot \frac{\sqrt{19}}{\sqrt{19}}\Rightarrow$

$\dfrac{-6\sqrt{19} }{19 \cdot 19} \\ \\ \Rightarrow -\dfrac{6\sqrt{19} }{361}$

$p(1/4) = -\dfrac{6\sqrt{19} }{361}$

3 0

3 years ago

1. The perimeter of the square is f(x) = 4x, where x is the side of the square. Find the domain of the function.

Mkey [24]

If the perimeter of the square is 4x then the domain of the function will be set of rational numbers and the domain of the function y=3x+8(3-x) is set of real numbers.

Given The perimeter of the square is f(x)=4x and the function is y=3x+8(3-x)

We will first solve the first part in which we have been given that the perimeter of the square is 4x and we have to find the domain of the function.

First option is set of rational numbers which is right for the function.

Second option is set of whole numbers which is not right as whole number involves 0 also and the side of the square is not equal to 0.

Third option is set of integers which is not right as integers involve negative number also and side of square cannot be negative.

Hence the domain is set of rational numbers.

Now we will solve the second part of the question

f(x)=3x+8(3-x)

we have not told about the range of the function so we can put any value in the function and most appropriate option will be set of real numbers as real number involve positive , negative and decimal values also.

Learn more about perimeter here brainly.com/question/19819849

#SPJ10

6 0

2 years ago

Read 2 more answers

Need help please answer asap

Vikki [24]

Answer:

$2x = x + 15$

Step-by-step explanation:

Angle AGH and GHD are corresponding angles, meaning they are equal. So in order to find the equation that can be used to solve for x we need to equate both angles AGH and GHD to each other.

$m < AGH\: \: \: = \: \: \: m < GHD \\ (x + 15) = (2x) \\ 15 = 2x - x \\ 15 = 1x \\ 15 = x$

They did not ask us to solve for x but I did it in case, however we can see that the answer we got corresponds with

$(1) \:2x = x + 15$

4 0

2 years ago

Read 2 more answers