The original or accepted value for the percent by mass of water in a hydrate = 36%
Percen by mass of water in the hydrate determined by the student
in the laboratory = 37.8%
So the difference between the actual and the percent by mass in water determined by student = (37.8 - 36.0)%
= 1.8%
So the percentage of error made by the student = (1.8/36) * 100 percent
= (18/360) * 100 percent
= ( 1/20) * 100 percent
= 5 percent
So the student makes an error of 5%. Option "1" is the correct option.
Answer:
You need 8,53 L of ammonia
Explanation:
Global reaction of remotion of nitrogen oxide with ammonia is:
4 NH₃ + 6 NO ⇒ 5 N₂ + 6 H₂O
This balanced equation shows that 4 NH₃ moles reacts with 6 NO moles.
With 100% yield and temperature and pressure constants it is possible to apply Avogadro's law. This law is an experimental gas law relating the volume of a gas to the amount of substance of gas present. The formula is:

Where:
V₁ is the NO volume = 12,8L
n₁ are NO moles = 6
n₂ are NH₃ moles = 4
V₂ is NH₃ volume, the unknown.
Thus, V₂ are 8,53 L of ammonia
I hope it helps!
Answer:
-) 2-methylbut-2-ene
-) 2-methylbut-1-ene
-) 3-methylbut-1-ene
Explanation:
in this case, the hydration of alkenes is a <u>marknovnikov reaction</u>, this means that the "OH" group would be added in the <u>most substituted carbon</u> of the double bond. (Figure 1)
For 2-methylbut-2-ene the most substituted carbon is the <u>tertiary carbon</u> (the carbon in the right of the double bond), so we will obtain the desired molecule. In 2-methylbut-1-ene the most substituted carbon is again the <u>tertiary carbon</u> (the carbon in the bottom of the double bond), so we will obtain 2-methyl-2-butanol. Finally, for 3-methylbut-1-ene the carbocation would be formed on carbon 3, this is a secondary carbocation. We can obtain a most stable carbocation if we do a <u>hydride shift</u> (Figure 2). With this new molecule is possible to obtain 3-methylbut-1-ene.
a. Negative
Explanation:
We have to look at its oxidation (burning, explosion) of TNT:
4 C₇H₅N₃O₆ + 21 O₂ → 28 CO₂ + 10 H₂O + 6 N₂ + heat
So trinitrotoluene need more oxygen atoms that is have to be fully oxidized so the oxygen balance will be negative.
An empirical formula with which you calculate the oxygen balance percent (OB %) is:
OB % = (-1600 / molecular wight) × [2X + (Y/2) + M - Z)
were
X = number of carbon atoms
Y = number of hydrogen atoms
M = number of metal atoms
Z = number of oxygen atoms
For TNT:
OB % = (-1600 / 227.13) × [2×7 + (5/2) + 0 - 6)
OB % = -73.97 %
So the oxygen balance percent is negative.
Learn more about:
oxidation of TNT
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