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xenn [34]
3 years ago
9

Perform the following metric conversions: Please explain bc I really dont get it at ALL !!!!

Chemistry
1 answer:
makkiz [27]3 years ago
7 0

Answer:

0.2007 nm

3.57 cm

0.01478 g

8280000 pg

Explanation:

1)200.7 pm

1 picometer is equal to 0.001 nanometer.

1 nm = 1000 pm

200.7 pm× 1 nm / 1000 pm  = 0.2007 nm

2)0.000357 hm

1 hectometer is equal to 10,000 centimeter.

1 hc = 10,000 cm

0.000357 hc× 10,000 cm / 1 hc = 3.57 cm

3) 14.78 mg

1 gram is equal to 1000 milligram.

1 g = 1000 mg

14.78 mg × 1 g/1000 mg = 0.01478 g

4)8.280 µg

1 microgram is equal to 10⁶ picogram.

1 µg = 1000000 pg

8.280 µg× 10⁶ pg/ 1µg = 8.280×10⁶ pg or 8280000 pg

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a 125 g chunk of aluminum at 182 degrees Celsius was added to a bucket filled with 365 g of water at 22.0 degrees Celsius. Ignor
Diano4ka-milaya [45]
<h3>Answer:</h3>

32.98°C

<h3>Explanation:</h3>

We are given the following;

Mass of Aluminium as 125 g

Initial temperature of Aluminium as 182°C

Mass of water as 265 g

Initial temperature of water as 22°C

We are required to calculate the final temperature of the two compounds;

First, we need to know the specific heat capacity of each;

Specific heat capacity of Aluminium is 0.9 J/g°C

Specific heat capacity of water is 4.184 J/g°C

<h3>Step 1: Calculate the Quantity of heat gained by water.</h3>

Assuming the final temperature is X°C

we know, Q = mcΔT

Change in temperature, ΔT = (X-22)°C

therefore;

Q = 365 g × 4.184 J/g°C × (X-22)°C

    = (1527.16X-33,597.52) Joules

<h3>Step 2: Calculate the quantity of heat released by Aluminium </h3>

Using the final temperature, X°C

Change in temperature, ΔT = -(X°- 182°)C (negative because heat was lost)

Therefore;

Q = 125 g × 0.90 J/g°C × (182°-X°)C

  = (20,475- 112.5X) Joules

<h3>Step 3: Calculating the final temperature</h3>

We need to know that the heat released by aluminium is equal to heat absorbed by water.

Therefore;

(20,475- 112.5X) Joules = (1527.16X-33,597.52) Joules

Combining the like terms;

1639.66X = 54072.52

             X = 32.978°C

                = 32.98°C

Therefore, the final temperature of the two compounds will be 32.98°C

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