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3 years ago

12

Which electron requires the most ionization energy - the 1st, 2nd or 3rd electron on a sodium atom? Support your answer using at

omic structure. (EX: energy levels, nuclear charge, attraction).

1 answer:

kicyunya [14]3 years ago

6 0

Answer:

3rd

Explanation:

I dont know how to to this explanation to be honest

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What is the use of the crystallisation process?

ioda

to obtain pure salt from seawater.
in order to obtain pure crystals of a substance from an impure mixture.
obtain pure alum crystals from an impure alum.

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2 years ago

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A 3000 MWt fast reactor has a 42% efficiency. This reactor operates for 23 months followed by a 1 month down time for refueling

n200080 [17]

Answer:

capacity factor = 0.952

Availability factor = 0.958

Explanation:

1) capacity factor

capacity factor = actual power output / maximum power output

= (actual power output)/(efficiency * rated power output)

$= \frac{1200}{\frac{42}{100}*3000}$

= 0.952

2) Availability factor

Availability factor = Actual operation time period/ total time period

= 23/24 = 0.958

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3 years ago

5. Why did you categorize the reactions the way you did? What do your physical reactions have in common? What do your chemical r

lapo4ka [179]

Answer:

What r u trying to ask? you need to put more stuff in your question on here so we can answer it.

Explanation:

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3 years ago

Given the reaction:CO2 + 6 H2O==> C6H12O6 + 6 O2

kari74 [83]

For every 1 mole of C6H12O6, you need 6 moles of water. Multiply the 2.5 moles you are trying to make by the 6 of water you need, and 4) 15 is your answer.

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3 years ago

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What is the solubility of MgCO₃ in a solution that contains 0.080 M Mg²⁺ ions? (Ksp of MgCO₃ is 3.5 × 10⁻⁸)

Alchen [17]

Answer: 4.4 x 10^-7

Explanation:

The dissociation equation for this reaction is:

MgCO3 (s) → Mg+2 (aq) + CO3-2 (aq)

$\text { So, } k_{s p}=(x+0.08) x$ (Here 0.08 >>> x )

$\begin{aligned}\Rightarrow 3.5 \times 10^{-8} &=0.08 \times x \\\Rightarrow x &=\frac{3.5}{0.08} \times 10^{-8} \\&=4.37 \times 10^{-7} \\\Rightarrow x & \approx 4.4 \times 10^{-7} \mathrm{~M}\end{aligned}$

So the solubility MgCO₃ in a solution that containing 0.080 M Mg²⁺ is 4.4 x 10^-7

7 0

2 years ago