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Butoxors [25]
4 years ago
10

a 100g sample of material requires 5104.5 joules of heat energy to raise its temperature from 20 degrees Celsius to 80 degrees C

elsius. what is the specific heat capacity of the material?
Chemistry
2 answers:
KengaRu [80]4 years ago
6 0

Answer:

The specific heat of the material is 0.851 J/g°C

Explanation:

Step 1: Data given

Mass of the sample = 100 grams

Amount of heat required = 5104.5 Joules

Initial temperature = 20.0°C

Final temperature = 80.0 °C

Step 2: Calculate the specific heat of the material

Q = m* c¨* ΔT

⇒with Q = the amount of energy = 5104.5 J

⇒with m = the mass of the material = 100 grams

⇒with c = the specific heat of the material = TO BE DETERMINED

⇒with ΔT = the change of temperature = T2 - T1 = 80.0 °C - 20.0 °C = 60.0 °C

5104.5 = 100 * c * 60

c = 5104.5 / (100*60)

c =  0.851 J/g°C

The specific heat of the material is 0.851 J/g°C

levacccp [35]4 years ago
5 0

Answer: 0.85075J/g.K

Explanation:

Mass of the material = 100g

Energy (Q) = 5104.5J

T1 = 20°C = 293K

T2 = 80°C = 353K

Formula for heat energy (Q) = mc ∇T

Q = mc∇T

∇T = T2 - T1

∇T = 353K - 293K = 60K

Q = mc∇T

C = Q / m∇T

C = (5104.5) / (100 * 60)

C = 0.85075 J/gK

The specific heat capacity of the material is 0.85075J/gK.

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VLD [36.1K]

Answer:

Different types of isotopes are used for different materials or objects. For radiometric dating, uranium-235 is considered best for it while carbon-14 is used for dating of rocks. It is also used for dating of wood samples.

Explanation:

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3 years ago
How many quarts of pure antifreeze must be added to 5 quarts of a 20 ntifreeze solution to obtain a 50 ntifreeze solution?
Ede4ka [16]

Quarts of pure antifreeze must be added to 5 quarts of a 20 antifreeze solution to obtain a 50 antifreeze solution is 3.

Antifreeze solution is a solute that lowers the freezing point of the liquid in a solution.

For calculating the amount of quarts of pure antifreeze solution added can be given by:

5×20/100 + x × 100% = (x+5) × 50/100

Where, x is the amount of antifreeze required for addition and pure antifreeze is 100% of the antifreeze taken.

1 + x = (x+5) 0.5

1 + x = 0.5x + 2.5

0.5x = 1.5

x = 3

So, 3 quarts of pure antifreeze must be added to 5 quarts of a 20 antifreeze solution to obtain a 50 antifreeze solution.

Learn more about Antifreeze solution here, brainly.com/question/14619701

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5 0
2 years ago
How many atoms are present in 98.1 grams of Ar? You may report your numerical answer in scientific notation use e-notation.
Andrei [34K]

Answer:

1.48 × 10²⁴ atoms

Explanation:

Step 1: Calculate the moles of argon

Argon is a noble gas, whose molar mass is 39.95 g/mol. We will use this data to find the moles corresponding to 98.1 grams of argon.

98.1g \times \frac{1mol}{39.95g} =2.46 mol

Step 2: Calculate the atoms of argon

In order to calculate the number of atoms of argon in 2.46 moles of argon, we have to consider the Avogadro's number: there are 6.02 × 10²³ atoms of Ar in 1 mole of Ar.

2.46mol \times \frac{6.02 \times 10^{23}atoms  }{1mol} = 1.48 \times 10^{24}atoms

6 0
3 years ago
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