Answer:
43.93 g/mol
Explanation:
The mass of the gas before reaction = 52.1487 g
The mass of the gas after reaction = 52.1098 g
Mass of gas generated = 0.0389 g
Moles of the gas = 
The formula for the calculation of moles is shown below:

Thus,


Molar mass of the gas = 43.93 g/mol
I’m not an expert and I haven’t taken chemistry in like a year but i believe you use stoichiometry to do this equation. It should look something like this.
Answer:
0.47 M
Explanation:
The concentration of the solution can be calculated using the following equation:

<u>Where:</u>
V: is the volume of the solution = 68.6x10⁻² L
η: is the moles of cobalt (II) sulfate
m: is the mass of cobalt (II) sulfate = 89.94 g
M: is the molar mass of cobalt (II) sulfate = 281.103 g/mol
The concentration of cobalt (II) sulfate is:
We used the molar mass of the cobalt (II) sulfate heptahydrate (281.103 g/mol) since it is one of the most common salts of cobalt.
Therefore, the concentration of a solution of cobalt (II) sulfate is 0.47 M (assuming that the cobalt (II) sulfate is heptahydrate).
I hope it helps you!
Answer:
it should be 310.18 g/mol :)