All categories

3 years ago

How would you determine which isotope pair to use for a particular material?

Chemistry

1 answer:

VLD [36.1K]3 years ago

7 0

Answer:

Different types of isotopes are used for different materials or objects. For radiometric dating, uranium-235 is considered best for it while carbon-14 is used for dating of rocks. It is also used for dating of wood samples.

Explanation:

Carbon-14 and uranium-235 are used for different materials or objects for measuring the age of these materials. These two isotopes are radioactive in nature which means they emit gamma radiations which allow us to find the age of different objects. Carbon-14 has a low half life so it can be used for those objects which are present before thousands of years while uranium-235 is used for materials which are millions of years old due to high half life.

You might be interested in

This diagram is attempting to compare the sizes of the four inner planets. What is wrong with this diagram?

Simora [160]

Answer:

points

Explanation:

6 0

3 years ago

Read 2 more answers

2.50 L of a gas at standard temperature and pressure is compressed to 575 mL. What is the new pressure of the gas

BartSMP [9]

Answer:

reek

Explanation:

5 0

3 years ago

How many carbon atoms are there on the reactant side of this equation?

amid [387]

Its obviously D like what are you stupid lol jk don’t take it to heart kid

4 0

3 years ago

What pressure, in atm, would be exerted by 0.023 grams of oxygen (O2) if it occupies 31.6 mL at 91

Vikentia [17]

Answer: A pressure of 0.681 atm would be exerted by 0.023 grams of oxygen $(O_2)$ if it occupies 31.6 mL at $91^{o}C$ .

Explanation:

Given : Mass of oxygen = 0.023 g

Volume = 31.6 mL

Convert mL into L as follows.

$1 mL = 0.001 L\\31.6 mL = 31.6 mL \times \frac{0.001 L}{1 mL}\\= 0.0316 L$

Temperature = $91^{o}C = (91 + 273) K = 364 K$

As molar mass of $O_2$ is 32 g/mol. Hence, the number of moles of $O_2$ are calculated as follows.

$No. of moles = \frac{mass}{molar mass}\\= \frac{0.023 g}{32 g/mol}\\= 0.00072 mol$

Using the ideal gas equation calculate the pressure exerted by given gas as follows.

PV = nRT

where,

P = pressure

V = volume

n = number of moles

R = gas constant = 0.0821 L atm/mol K

T = temperature

Substitute the value into above formula as follows.

$PV = nRT\\P \times 0.0316 L = 0.00072 mol \times 0.0821 L atm/mol K \times 364 K\\P = \frac{0.00072 mol \times 0.0821 L atm/mol K \times 364 K}{0.0316 L}\\= 0.681 atm$

Thus, we can conclude that a pressure of 0.681 atm would be exerted by 0.023 grams of oxygen $(O_2)$ if it occupies 31.6 mL at $91^{o}C$ .

4 0

3 years ago

Explain what a chromosome is in your own words.

Alex787 [66]

It’s a structure of nucleic acids and protein that can be found in the nucleus; it carries genetic information through genes

7 0

3 years ago

Read 2 more answers