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postnew [5]
3 years ago
11

How many moles are in 0.06 grams of iron

Chemistry
1 answer:
Eva8 [605]3 years ago
3 0
No of mole = reacting mass/ molar mass

No of mole = 0.06/56

No of mole = 0.00107mol....

Or...

1mole of iron contain 56gmol¯¹
:-x mole is contained in 0.06g

Porata
And you'll have..

x = 0.06/56

x = 0.00107mol.....
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Question 3 (1 point)
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Answer:

1. Formulae of hydrate is Na₂CO₃.10H₂O

2. Formulae of hydrate is CaSO₄.2H₂O

Explanation:

Q1. Mass of hydrated salt = 8.50 g mass

mass of anhydrous salt = 7.26 grams

mass of water lost = 1.24

Formula of hydrated salt = Na₂CO₃.xH₂O

Formula of anhydrous salt = Na₂CO₃

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Mole ratio of Na₂CO₃ to H₂O = 7.26/106 : 1.24/18

Mole ratio of Na₂CO₃ to H₂O = 0.0068 : 0.068

Mole ratio of Na₂CO₃ to H₂O = 1 :10

Therefore, formulae of hydrate is Na₂CO₃.10H₂O

Q2.  Mass of hydrated salt = 60.98 g mass

mass of anhydrous salt = 48.23 grams

mass of water lost = 12.75

Formula of hydrated salt = CaSO₄.xH₂O

Formula of anhydrous salt = CaSO₄

Molar mass of anhydrous salt is obtained as below where Ca = 40, S = 32, O = 16, H = 1

Molar mass of CaSO₄= (40 + 32 + 16 * 4) = 136 g

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Mole ratio of CaSO₄ to H₂O = 48.23/136 : 12.75/18

Mole ratio of CaSO₄ to H₂O = 0.35 : 0.70

Mole ratio of CaSO₄ to H₂O = 1 : 2

Therefore, formulae of hydrate is CaSO₄.2H₂O

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