Answer:
2N2H2SO4
Explanation:
this is your answer calculate
Au/Cr cell will run as a voltaic cell and Co/Zn cell will run as an electrolytic cell.
<h3>What is an electrolytic cell?</h3>
An electrolytic cell that uses electrical energy to enable a non-spontaneous redox reaction is known as an electrolytic cell.
Certain chemicals can be electrolyzed using electrolytic cells, which are electrochemical cells.
For example, water can be electrolyzed to create gaseous oxygen and gaseous hydrogen with the use of an electrolytic cell.
The following are the three essential parts of electrolytic cells:
Cathode (which is negatively charged for electrolytic cells)
Anode (which is positively charged for electrolytic cells)
Electrolyte
The reactions for each half cell is given by
; E° = 1.50 V
; E° = –0.74 V
; E° = –0.28 V
; E° = –0.76 V
When the Au/Cr cell will run as a voltaic cell and Co/Zn cell will run as an electrolytic cell, the a difference in the voltages is produced
= 2.24 V – 0.48 V = 1.76 V
Learn more about electrolytic cell:
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Answer:
The correct option is;
d 4400
Explanation:
The given parameters are;
The mass of the ice = 55 g
The Heat of Fusion = 80 cal/g
The Heat of Vaporization = 540 cal/g
The specific heat capacity of water = 1 cal/g
The heat required to melt a given mass of ice = The Heat of Fusion × The mass of the ice
The heat required to melt the 55 g mass of ice = 540 cal/g × 55 g = 29700 cal
The heat required to raise the temperature of a given mass ice (water) = The mass of the ice (water) × The specific heat capacity of the ice (water) × The temperature change
The heat required to raise the temperature of the ice from 0°C to 100°C = 55 × 1 × (100 - 0) = 5,500 cal
The heat required to vaporize a given mass of ice = The Heat of Vaporization × The mass of the ice
The heat required to vaporize the 55 g mass of ice at 100°C = 80 cal/g × 55 g = 4,400 cal
The total heat required to boil 55 g of ice = 29700 cal + 5,500 cal + 4,400 cal = 39,600 cal
However, we note that the heat required to vaporize the 55 g mass of ice at 100°C = 80 cal/g × 55 g = 4,400 cal.
The heat required to vaporize the 55 g mass of ice at 100°C = 4,400 cal
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