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4 years ago

Can I get some help please I’m lost :(

Chemistry

1 answer:

Molodets [167]4 years ago

7 0

Answer:

C) 11 g

Explanation:

first look to graph , you have x and y

x is mass of Fe

and y is mass of product

if the reaction consumes 2 g of Fe , ( look to x axis , look to 2 )

and go up until the black line touch the line of number 2

and go left and you will see the point become in the middle between 10 and 12

** 12 (11) 10 ***

Good Luck

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A person slips over banana pills. Give reason

zhenek [66]

Answer:

We slip when we step on a banana peel because the inner side of banana peel being smooth and slippery reduces the friction between the sole of our shoe and the surface of road.

8 0

3 years ago

Gaseous ethane will react with gaseous oxygen to produce gaseous carbon dioxide and gaseous water . Suppose 2.71 g of ethane is

DanielleElmas [232]

Answer:

Explanation:

Step 1:

The balanced equation for the reaction between gaseous ethane and gaseous oxygen. This is given below:

2C2H6 + 7O2 —> 4CO2 + 6H2O

Step 2:

Determination of the masses of C2H6 and O2 that reacted and the mass of CO2 produced from the balanced equation. This is illustrated below:

2C2H6 + 7O2 —> 4CO2 + 6H2O

Molar Mass of C2H6 = (12x2) + (6x1) = 24 + 6 = 30g/mol

Mass of C2H6 from the balanced equation = 2 x 30 = 60g

Molar Mass of O2 = 16x2 = 32g/mol

Mass of O2 from the balanced equation = 7 x 32 = 224g

Molar Mass of CO2 = 12 + (2x16) = 12 + 32 = 44g/mol

Mass of CO2 from the balanced equation = 4 x 44 = 176g

From the balanced equation above,

60g of C2H6 reacted with 224g of O2 to produce 176g of CO2.

Step 3:

Determination of the limiting reactant.

We need to determine the limiting reactant as it will be needed to obtain the maximum mass of CO2.

From the balanced equation above,

60g of C2H6 reacted with 224g of O2.

Therefore, 2.71g of C2H6 will react with = (2.71 x 224)/60 = 10.12g of O2.

From the above calculation, we can see that a higher mass of O2 is needed to react with 2.71g of C2H6, therefore, O2 is the limiting reactant.

Step 4:

Determination of the maximum mass of CO2 produced when 2.71 g of ethane is mixed with 7.6 g of oxygen.

The limiting reactant is used to determine the maximum mass.

From the balanced equation above,

224g of O2 produce 176g of CO2.

Therefore, 7.6g of O2 will produce = (7.6 x 176)/224 = 5.97g ≈ 6g of CO2

From the calculations made above, the maximum mass of CO2 produced is 5.97 ≈ 6g

5 0

4 years ago

Li + H2O → H2 + LiOH is it Balanced or Unbalanced

Sav [38]

Answer:

It is Unbalanced

Explanation:

2Li + 2H2O→ 2LiOH+ H2

8 0

3 years ago

Calculate the mass of NaCl needed to make 40% solution from 3kg of water ? Could you explain step by step please :-)

earnstyle [38]

Ok so 40 percent of 3000 grams which is 3 kg is 1200 grams
So you would need 1.2kg or 1200 grams to make a 40% solution

3 0

4 years ago

(a) ions in a certain volume of .20M NaCl (aq) are represented in the box above on the left. in the box above on the right, draw

mamaluj [8]

Answer:

The first picture attached is the diagram that accompanies the question.

The<u> second picture attached</u> is the diagram with the answer.

Explanation:

In the box on the left there are 8 Cl⁻ ions and 8 Na⁺ ions.

The dissociaton equation for NaCl(aq) is:

NaCl (aq) → Na⁺ (aq) + Cl⁻(aq)

The dissociation equation for CaCl₂ (aq) is:

CaCl₂ (aq) → Ca²⁺ (aq) + 2Cl⁻(aq)

A 0.10MCaCl₂ (aq) solution will have half the number of CaCl₂ units as the number of NaCl units in a 0.20M NaCl (aq) solution.

Thus, while the 0.20M NaCl (aq) solution yields 8 ions of Na⁺ and 8 ions of Cl⁻, the 0.10MCaCl₂ (aq) solution will yield 4 ions of Ca²⁺ (half because the concentration if half) and 8 ions of Cl⁻ (first take half and then multiply by 2 because the dissociation reaction).

Thus, your drawing must show 4 dots representing Ca²⁺ ions and 8 dots representing Cl⁻ ions in the box on the right.

4 0

3 years ago