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Vesna [10]
2 years ago
11

Researchers can use solvents to extract, or break apart, components of a cell or tissue to separate and/or isolate components. I

f you extracted some cells with a non-polar organic solvent, what would the solvent contain the MOST of at the end of the process
Chemistry
1 answer:
Tems11 [23]2 years ago
6 0

The cell membrane which is more fat permeable will be present at the end of the process.

Solvent extraction is a very important method if separating mixtures. The principle of solvent extraction is based on the idea of like dissolves like. A substance dissolves in the component of the system in which it is most soluble.

If a cell extract is dissolved in a nonpolar solvent, the cell membrane which is mostly permeable to nonpolar molecules will dissolve most in the solvent.

Learn more:brainly.com/question/14396802

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A container holds three gases: oxygen, carbon dioxide, and helium. The partial pressures of the three gases are 2.00 atm, 3.00 a
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Answer:

9.00 atm

For total pressure, you would add all the pressures together

7 0
3 years ago
Below is a list of substances. Some are mixtures and some are not. Select all of the substances which are homogeneous.
Papessa [141]

B the atmosphere

D. gasoline

C. a carbonated soft drink (without bubbles)


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3 years ago
In the coal-gasification process, carbon monoxide is converted to carbon dioxide via the following reaction: CO (g) + H2O (g) ⇌
Oksana_A [137]

Answer: Equilibrium constant is 0.70.

Explanation:

Initial moles of  CO = 0.35 mole

Volume of container = 1 L

Initial concentration of CO=\frac{moles}{volume}=\frac{0.35moles}{1L}=0.35M

Initial moles of  H_2O = 0.40 mole

Volume of container = 1 L

Initial concentration of H_2O=\frac{moles}{volume}=\frac{0.40moles}{1L}=0.40M

equilibrium concentration of CO=\frac{moles}{volume}=\frac{0.18moles}{1L}=0.18M [/tex]

The given balanced equilibrium reaction is,

                            CO(g)+H_2O(g)\rightleftharpoons CO_2(g)+H_2(g)

Initial conc.            0.35 M       0.40M       0     0

At eqm. conc.    (0.35-x) M   (0.40-x) M   (x) M    (x) M

The expression for equilibrium constant for this reaction will be,

K_c=\frac{[CO_2]\times [H_2O]}{[CO]\times [H_2O]}

K_c=\frac{x\times x}{(0.40-x)(0.35-x)}

we are given : (0.35-x)= 0.18

x = 0.17

Now put all the given values in this expression, we get :

K_c=\frac{0.17\times 0.17}{(0.40-0.17)(0.35-0.17)}

K_c=0.70

Thus the value of the equilibrium constant is 0.70.

5 0
3 years ago
A student was given four unknown solutions. Each solution was checked for. conductivity and tested with. phenolphthalein. The re
777dan777 [17]

Answer: (3) C

Explanation:

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3 years ago
How can you figure out the properties of a star?
Firlakuza [10]

Answer:

Measuring distances to stars through stellar parallax. Measuring distances to stars through the moving cluster method. Astronomers measure the temperature of a star by looking at the star's color and its spectrum. The apparent brightness of a star tells how bright it seems to us

Explanation:

3 0
3 years ago
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